如何在echo中插入第二个样式元素

I am having this piece of code in which a style element is added. How can I add a second style element in the same echo? per example: color: orange;

echo '<span class=\'Meta\' style=\'min-height:inherit\'>'.T('Read by: ').$out.'</span><br>';

Just add the rule separated by a semi-colon, in the same style attribute:

echo '<span class=\'Meta\' style=\'min-height:inherit; color:orange;\'>'.T('Read by: ').$out.'</span><br>';

I prefer using single and double quotes in combination, simpler to read and no need to escape quotes:

echo '<span class="Meta" style="min-height:inherit; color:orange;">'.T('Read by: ').$out.'</span><br>';
echo '<span class="Meta" style="min-height:inherit;color:orange">'.T('Read by: ').$out.'</span><br>';

The code needs to be more clear.

No need to add a new style element.

You can add it as a new child to style with semi-colon ;.

echo '<span class=\'Meta\' style=\'min-height:inherit; color:green; \'>'.T('Read by: ').$out.'</span><br>';

You can add more CSS properties by separating it with a ;

I would do the same thing differently, so as to make it more readable.

echo '<span class="Meta" style="min-height:inherit; color:green;">'. No need for extra \