I have the following URL:
When I type this URL in my browser's address bar, it gives me a JSON response, which I need in PHP. I tried using cURL to fetch it (see below code), but it didn't work — no response is printed on the page.
function get_json($url) {
$ch = curl_init();
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL, $url);
$data = curl_exec($ch);
$resultCode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
curl_close($ch);
if ($resultCode == 200) {
return json_decode($data);
} else {
return false;
}
}
$json = get_json('https://api.stackexchange.com/2.0/questions?page=1&pagesize=30&
key=VVq3kJHSjQ*7qgpiRaVoLA%28%28&site=stackoverflow');
echo '<pre>';
print_r($json);
How can I fetch this URL and convert it into a PHP array the right way?
Last I checked, all responses from the API were gzip'd:
$ch = curl_init();
curl_setopt_array($ch, array(
CURLOPT_URL => $url
, CURLOPT_HEADER => 0
, CURLOPT_RETURNTRANSFER => 1
, CURLOPT_ENCODING => 'gzip'
));
$data = curl_exec($ch);
var_dump($data);
var_dump(json_decode($data));
Setting CURLOPT_ENCODING
enables automatic un gzip'ing of the response, in addition to sending an Accept-Encoding: gzip
in the http request, although sending that header isn't strictly required for this to work.
Try this:
$json = json_decode(file_get_contents("https://api.stackexchange.com/.............."));
echo "<pre>";
print_r($json);
To return an array, use the second parameter in json_decode
and set it to true
.
if ($resultCode == 200) {
return json_decode($data, true);
} else {
return false;
}