使用复选框[复制]提交表单

I have a very simple question - how do I get a form to submit when I change the status of a checkbox

Here is my code

<form name="formName" id="formName" action="<?php echo $_SERVER['PHP_SELF'];?>" method="get">
<input type ="checkbox" name="categories1" value = "1" onClick="submit();">1</input>
</form>

in addition to submit() I have tried:

• this.form.submit()
• document.getElementById('formName').submit()
• this.parentNode.submit()

but none of these work. When I check or uncheck the box nothing happen

any clues?

</div>

Refer to the form name attribute:

document.formName.submit()

This works for me in both FF and IE:

<form name="formName" id="formName" action="" method="get">
<input type ="checkbox" name="categories1" value = "1" onclick="this.form.submit();">1</input>
</form>

found the problem - I had a submit button named submit - see Javascript form submit: Object doesn't support this property or method (IE7) for similar soln.

You can try the following

<form name="formName" id="formName" action="" method="get">
<input type ="checkbox" name="categories1" value = "1" **onchange**="this.form.submit();">1</input>
</form>