I have a date time string 2018-12-05 03:05:43 How I convert it to array like this format:
[2018, 12, 5, 3, 5, 43]
You could use explode() and merge()
$tmp1 = explode(' ', '2018-12-05 03:05:43');
$tmp2 = explode('-', $tmp1[0]);
$tmp3 = explode(':', $tmp1[1]);
$merge = array_merge($tmp2, $tmp3);
You can parse the date using PHP's DateTime class and output each component separately:
$date = date_create_from_format('Y-m-d H:i:s', '2018-12-05 03:05:43');
$array = array(
(int)$date->format('Y'),
(int)$date->format('m'),
(int)$date->format('d'),
(int)$date->format('H'),
(int)$date->format('i'),
(int)$date->format('s')
);
print_r($array);
Output:
Array (
[0] => 2018
[1] => 12
[2] => 5
[3] => 3
[4] => 5
[5] => 43
)
You can also use regex.
The pattern finds an optional zero and any digit(s).
The zero is not part of the capture thus will not be presented in the [1] array.
$str ="2018-12-05 03:05:43";
preg_match_all("/0*(\d+)/", $str, $arr);
$arr = $arr[1]; // only keep the capture
var_dump($arr);
Output:
array(6) {
[0]=>
string(4) "2018"
[1]=>
string(2) "12"
[2]=>
string(1) "5"
[3]=>
string(1) "3"
[4]=>
string(1) "5"
[5]=>
string(2) "43"
}