关于您的这篇 遗传算法求解TSP问题(python版),测试文件怎么从您这获得
import random
# 定义TSP问题的邻域结构
graph = {
'A': {'B': 2, 'C': 1},
'B': {'A': 2, 'C': 1},
'C': {'A': 1, 'B': 2, 'C': 1},
'D': {'A': 1, 'B': 2, 'C': 1},
'E': {'A': 1, 'B': 2, 'C': 1}
}
# 定义种群大小和进化代数
POP_SIZE = 50
GENE_SIZE = 10
# 定义适应度函数
def fitness_function(solution):
# 计算路径长度
length = sum([graph[node]['weight'] for node in solution])
return length
# 定义交叉函数
def crossover(parent1, parent2):
# 选择交叉点
crossover_point = random.randint(0, len(parent1) - 1)
# 生成子代
child1 = parent1[:crossover_point] + parent2[crossover_point:]
child2 = parent2[:crossover_point] + parent1[crossover_point:]
return child1, child2
# 定义变异函数
def mutation(solution):
# 选择变异点
mutation_point = random.randint(0, len(solution) - 1)
# 在变异点处随机选择一个位置
mutation_value = random.randint(0, 100)
# 将变异值设置为随机值
solution[mutation_point] = mutation_value
return solution
# 定义遗传算法函数
def genetic_algorithm(graph, POP_SIZE, GENE_SIZE):
# 初始化种群
population = []
for i in range(POP_SIZE):
population.append([graph[node]['weight'] for node in graph[solution[i]]])
# 选择交叉点和变异点
crossover_point = 0
mutation_point = 0
for i in range(GENE_SIZE):
# 生成下一代种群
offspring = []
for j in range(POP_SIZE):
offspring.append(population[j][random.randint(0, len(population[j]) - 1):])
# 选择交叉点
if random.random() < 0.5:
crossover_point = random.randint(0, len(offspring[0]) - 1)
offspring[0], offspring[1] = offspring[1], offspring[0]
# 选择变异点
if random.random() < 0.1:
mutation_point = random.randint(0, len(offspring[0]) - 1)
offspring[0][mutation_point] = random.randint(0, 100)
# 更新种群
population = offspring
# 评估适应度
fitness_scores = [fitness_function(solution) for solution in population]
# 选择最优解
best_solution = max(fitness_scores)
这篇写的还挺好的,可以看一下。https://blog.csdn.net/qq_27163583/article/details/125207836
%% 计算适应度,即路径的长度
function fit=fitness(Chro,C)
for i=1:size(Chro,1)
possible_sol=Chro(i,:); % 拿到1个染色体
possible_sol=[possible_sol possible_sol(1)]; % 将第一个城市坐标补充到末尾
dist=0; % 用于计算总距离
for j=1:length(possible_sol)-1
city1=possible_sol(j); % 第j个城市的编号
city2=possible_sol(j+1); % 第j+1个城市的编号
city1_C=C(city1,:); % 第j个城市的坐标
city2_C=C(city2,:); % 第j+1个城市的坐标
dist=dist+norm(city1_C-city2_C); % 第j个城市和第j+1个城市的距离
end
fit(i)=dist;
end
end