关于嵌套列表取值的问题，如何解决？

我只想要 title 的key和值，key :"answer" 的值："某个英文字母" ，对应其answer 值的"choice_info" 的值

输出比如：
广东省高速公路网规划（2020—2035年）的具体目标是通往粤北有（）条高速公路通道
D
8

如果是多选题也是一样的输出

将你的列表复制到一个.json文件中，然后打开取值

代码如下：

# coding:utf-8
import json

with open( 'info.json') as f:
    a = json.load(f)
for each in a:
    title = each['title'].replace('\n','')
    ans = each['choice_answer']
    choices = each['option']
    print(f"题目：{title}")
    for i in ans:
        for option in choices:
            if i == option['choice_serial']:
                print(f"选项:{i}")
                print(f"答案:{option['choice_info']}")
                break
    print()

运行结果如下：

#其实上面的列表就是一个json,把它存入文件test.json可以如下取值
#你的示例全是单选题，如果有多选，最好给出数据样本
import json

with open( 'test.json', encoding = 'utf-8') as f:
    l = json.load(f)    
    for i in l:
        print('title:', i['title'], 'answer:', i['answer'], 'choice_info:',i['option']['ABCD'.index(i['answer'])]['choice_info'])

爬虫弄的数据吗？把你的数据来个data.json()，变成字典或者列表，选取那都行。
或者直接这样写，因为你的null没有引号，复制你的数据，弄成表格，然后你想怎么取都行


null=''
dd=你的数据
answer={'A':0,'B':1,'C':2,'D':3}
d=[]
for i in range(len(dd)):
    num=answer[dd[i]['answer']]
    df={'title':dd[i]['title'],'answer':dd[i]['answer'],'choice_info':dd[i]['option'][num]['choice_info']}
    d.append(df)
data=pd.DataFrame(d)
print(data)

https://www.baidu.com/link?url=wPssb-R6Qm0TneXbSZLaoB3x94SVJtFvd-bMIe5AB3BcE4iePUxHWeH2ScHuUNSVWQksnCqiCCQp0LXAfWZKiKrOMuAq7BZoFwBFH3Y5QhS&wd=&eqid=fbfb3d36001294af0000000263ec41e7

# 用 json 将数据读出，存放到a
a = .....

for i in range(len(a)):
    print('第{}题：'.format(i+1))
    print(a[i]['title'])
    print('答案：',a[i]['answer'])
    print(a[i]['choice_answer'])
    print([n['choice_info'] for n in a[i]['option'] if n['choice_serial'] in a[i]['choice_answer']])
    print()

把你的获取到的这些数据转为json:

import json
d=json.load(data)
for i in range(len(d)):
      print(d[i]['answer'],d[i]['choice_answer'])


# 使用json读取数据，转换成dict或者list, 放到list中
list = ...

for item in list:
    text = item['title']
    answer = item['answer']           
    option = item['aption']
    for val in option:
        if type(answer) == str :
            if val['choice_serial'] == answer:
                text += answer + "\r\n" + val['choice_info'] + "\r\n"
        else :
            text += ",".join(answer) + "\r\n"
            for ans in answer:
                if val['choice_serial'] == ans:
                    text += val['choice_info'] + ","
            text += "\r\n"
        print(text)

可以看下python参考手册中的 python- 嵌套的列表推导式