public String getPairSumTo(int[] addends, int targetSum) {
// TODO: write statements here
int indexone;
int j;
String output = "0";
if(addends.length<2){
output = "0";
} else {
for (indexone = 0; indexone < addends.length; indexone++) {
for (j = indexone + 1; j < addends.length; j++) {
if (addends[indexone] + addends[j] == targetSum) {
output = indexone + ", " + j;
} else{
output = "0";
}
}
}
}return output;
}
已经尽力了，还是求不出来。
要求
getPairSumTo(new int[] {1, 2, 3, 4, 5, 6}, 10)
最后会return
"4, 6"
双层for循环判断，你这个代码逻辑不对，代码修改如下：
public String getPairSumTo(int[] addends, int targetSum){
String s="";
for(int i=0;i<addends.length;i++){
for(int j=i+1;j<addends.length;j++){
if(addends[i]+ addends[j]== targetSum){
s = Integer.toString(addends[i]) + "," + Integer.toString(addends[j]);
return s;
}
}
}
return s;
}
希望对您有所帮助，有用的话采纳一下吧
public class Main {
public static void main(String[] args) {
getPairSumTo(new int[]{1,2,3,4,5,6}, 6);
}
//输出数组数组中两个数值之和等于targetSum的数
public static void getPairSumTo(int[] addends, int targetSum) {
int indexone;
int j;
if(addends.length>2){
//外层for循环之所以要indexone < addends.length - 1，是为了防止内层for循环j = indexone + 1造成数组越界
for (indexone = 0; indexone < addends.length - 1; indexone++) {
for (j = indexone + 1; j < addends.length; j++) {
if (addends[indexone] + addends[j] == targetSum) {
//每有一组符合要求的数据就输出，避免漏掉
System.out.println(addends[indexone] + ", " + addends[j]);
}
}
}
}
}
}