python3矩阵问题

import numpy as np 
list=[[1,2],[3,4],[5,6]] 
t=np.array(list)
print(t)
t=np.arange(24).reshape(4,6)
print(t)
print(t.ndim)
print(t.size)
print(t.shape)
t.shape=(3,2)
print(t)

t.shape=(3,2)这里报错了，为什么改变矩阵失败了？应该怎么改变？

t.reshape(3,2)

• 你可以参考下这个问题的回答, 看看是否对你有帮助, 链接: https://ask.csdn.net/questions/7473898

class Solution:
    def spiralOrder(self, matrix: List[List[int]]) -> List[int]:
        m = len(matrix)
        if m == 0:
            return []
        n = len(matrix[0])
        if n == 0:
            return 0
        res  = []
        dir = 1 # 方向：1 右 2 下 3 左 4 上
        x = 0 # 起始列标
        y = 0 # 起始行标
        while True:
            if x == -1 or x == n or y == -1 or y == m or matrix[y][x] == None:
                break

            res.append(matrix[y][x])
            matrix[y][x] = None
            
            if dir == 1 and ( x + 1 == n or matrix[y][x + 1] == None):
                dir = 2
            elif dir == 2 and (y + 1 == m or matrix[y + 1][x] == None):
                dir = 3
            elif dir == 3 and (x - 1 == -1 or matrix[y][x - 1] == None):
                dir = 4
            elif dir == 4 and (y - 1 == -1 or matrix[y - 1][x] == None):
                dir = 1

            if dir == 1:
                x += 1
            elif dir == 2:
                y += 1
            elif dir == 3:
                x -= 1
            elif dir == 4:
                y -= 1
        return res