函数总是在echo期间首先执行？ [重复]

Is there any why I can write this code by calling echo once to get output as hello Sam?

This is the PHP code :

<?php  

    function moo() {
        echo 'Sam';
    }

    echo 'hello ' . moo();

?>

The output is Samhello The parsing is R to L. I can achieve the desired output by writing echo on 2 separate lines as :

<?php  

    function moo() {
        echo 'Sam';
    }

    echo 'hello ';
    echo moo();

?>

but is there a way to do this in one line?

</div>

Instead of having the function echo, just have it return the string you want to print. Then let the caller decide what to do with it - in this case, echo it:

function moo() {
    return 'Sam';
}

echo 'hello ' . moo();

Edit: Adding explanation (not the author of the answer) rather than leaving comment.

The difference between a "return" and an inline concat is that for the initial function (the echo statement) to work, it needs to run the function (in your code, it is moo() ) prior to outputting the initial echo statement.

This is no different to the following example:

echo number_format(get_something_from_database_which_is_a_number());

You want the function get_something_from_database_which_is_a_number() to return the value prior to the number_format() function to then format it nicely.

If you use a return statement, the function itself will run, but then return your string back to the initial function call (in your case an echo) statement.