用新线替换段落中的所有点，除了数字之间的点和Dr.博士先生，Bsc之后。 ......等

Replace all dots in paragraph with new line except that dots between numbers and after Dr., Mr., Bsc. .... etc.

For Example:

Consider this Paragraph

My name is Ayman. I'm 31 years. I'm 1.92M. I have BSc. degree in Computer Engineering

I want to apply such REGEX and convert it as the following:

My name is Ayman.
I'm 31 years.
I'm 1.92M.   <===== note the '.' between 1 and 92 did not replace with new line
I have BSc. degree in Computer Engineering  <=== the same . after BSc did not replace with new line

I tried the following but this REGEX replace all dots.

$desc['contents']=preg_split("/(?<!\..)([\?\!\.]+)\s(?!.\.)/",$desc['contents'],-1, PREG_SPLIT_DELIM_CAPTURE);

Try

$str = "My name is Ayman. I'm 31 years. I'm 1.92M. I have BSc. degree in Computer Engineering";

$str = preg_split("/([\?\!\.]+)(?=\s+[A-Z])/",$str);

foreach($str as $new_str)
{
    echo $new_str.".<br />";
}

Output

My name is Ayman.
I'm 31 years.
I'm 1.92M.
I have BSc. degree in Computer Engineering.

Demo

You can use this regex for search:

(?:BSc|[JSMD]r|Mr?s|\d)\.(*SKIP)(*F)|(\.\h*)

and replace by "$1 "

RegEx Demo

$str = preg_replace('/(?:BSc|[JSMD]r|Mr?s|\d)\.(*SKIP)(*F)|(\.\h*)/i', '$1
', $str);

You can add more word patterns in (?:BSc|[JSMD]r|Mr?s|\d) that you want to ignore before DOT.

(*SKIP)(*F) together provide a nice alternative of restriction that you cannot have a variable length lookbehind in above regex.

I think you can use capturing group like this:

/\.\d|BSc\.|Mrs?\.|Dr\.|([.!?])/

And replace all matches of substitution \1 with ..

Note that I think you need to ignore . before numbers like .1 not after a number like And counter is 30.