来自Guzzle的PHPUnit和模拟请求

I have a class with the following function :

public function get(string $uri) : stdClass
{
    $this->client = new Client;
    $response = $this->client->request(
        'GET',
        $uri,
        $this->headers
    );

    return json_decode($response->getBody());
}

How can I mock the request method from PHPUnit? I tried different ways but it always tries to connect to the uri specified.

I tried with :

    $clientMock = $this->getMockBuilder('GuzzleHttp\Client')
        ->setMethods('request')
        ->getMock();

    $clientMock->expects($this->once())
        ->method('request')
        ->willReturn('{}');

But this didn't work. What can I do? I just need to mock the response to be empty.

Thanks

PD : Client comes from (use GuzzleHttp\Client)

I think as suggested is better to use http://docs.guzzlephp.org/en/stable/testing.html#mock-handler

as it looks like the most elegant way to do it properly.

Thank you all

The mocked Response doesn't need to be anything in particular, your code just expects it to be an object with a getBody method. So you can just use a stdClass, with a getBody method which returns some json_encoded object. Something like:

$jsonObject = json_encode(['foo']);
$uri = '/foo/bar/';

$mockResponse = $this->getMockBuilder(\stdClass::class)->getMock();

mockResponse->method('getBody')->willReturn($jsonObject);

$clientMock = $this->getMockBuilder('GuzzleHttp\Client')->getMock();

$clientMock->expects($this->once())
    ->method('request')
    ->with(
        'GET', 
        $uri,
        $this->anything()
    )
    ->willReturn($mockResponse);

$result = $yourClass->get($uri);

$expected = json_decode($jsonObject);

$this->assertSame($expected, $result);