问题:输入"a+b"或"a-b"...,程序结束!求解。
public class Calculater
{
public static void main(String[] args){
System.out.print("格式:\"a+b\"\"a-b\"务必带上双引号!请输入运算方式:");
java.util.Scanner s=new java.util.Scanner(System.in);
String input1=s.next();
switch(input1){
case "a+b":
System.out.print("你选择了加法,请按a+b的格式输入:");
double end1=s.nextDouble();
System.out.print("运算结果是:"+end1);
break;
case "a-b":
System.out.print("你选择了加法,请按a-b的格式输入:");
double end2=s.nextDouble();
System.out.print("运算结果是:"+end2);
break;
case "a*b":
System.out.print("你选择了加法,请按a*b的格式输入:");
double end3=s.nextDouble();
System.out.print("运算结果是:"+end3);
break;
case "a/b":
System.out.print("你选择了加法,请按a/b的格式输入:");
double end4=s.nextDouble();
System.out.print("运算结果是:"+end4);
break;
case "a%b":
System.out.print("你选择了加法,请按a%b的格式输入:");
double end5=s.nextDouble();
System.out.print("运算结果是:"+end5);
break;
}
}
}
你输入a+b 不加引号就能进去了, 但是你这逻辑不对啊, 实现不了 计算器的功能
改好了哈哈
public class Calculater
{
public static void main(String[] args){
System.out.println("欢迎使用计算器");
System.out.println("此计算器的功能有:加法、减法、乘法、除法、取余");
java.util.Scanner s=new java.util.Scanner(System.in);
System.out.print("第一个数字:");
double end1=s.nextDouble();
System.out.print("第二个数字:");
double end2=s.nextDouble();
System.out.println("请输入你需要的功能:");
String input1=s.next();
switch(input1){
case "加法":
System.out.println("结果为:"+(end1+end2));
break;
case "减法":
System.out.println("结果为:"+(end1-end2));
break;
case "乘法":
System.out.println("结果为:"+(end1*end2));
break;
case "除法":
System.out.println("结果为:"+(end1/end2));
break;
case "取余":
System.out.println("结果为:"+(end1%end2));
break;
default :
System.out.println("请输入数字");
}