（能用必采纳）（改错）python matplotlib作图

假设在二维平面内一个点（初始位置设为（0，0））一次能随机的沿着东西南北的其中一个方向走一个单位，求100000次后以该点与原点的距离为y轴走的次数为x轴的图像，以下是我个人的代码：
import random
import matplotlib.pyplot as plt
import numpy as np
xl = [0]
y = [0]
for i in range(100000):
mydir = random.randint(1,4)
mystep = 1
if mydir == 1:
xl.append(xl[-1]+mystep)
if mydir == 2:
xl.append(xl[-1]-mystep)
if mydir == 3:
y.append(y[-1]+mystep)
xl.append(xl[-1]+(xl[-1]**2+y[-1]**2)**0.5)
if mydir == 4:
y.append(y[-1]-mystep)
xl.append(xl[-1]+(xl[-1]**2+y[-1]**2)**0.5)

xl=np.array(xl)
plt.plot(np.abs(xl))
plt.show()
plt.close()

修改后如下
有帮助望采纳~

import random
import matplotlib.pyplot as plt
x=0
y=0
distance=[]
for i in range(100000):
    mydir = random.randint(1,4)
    if mydir == 1:
        x+=1
        distance.append((x**2+y**2)**0.5)
    elif mydir == 2:
         y+=1
         distance.append((x**2+y**2)**0.5)
    elif mydir == 3:
         x-=1
         distance.append((x**2+y**2)**0.5)
    else:
         y-=1
         distance.append((x**2+y**2)**0.5)

plt.plot(range(100000),distance)
plt.show()
# plt.close()

 
import matplotlib.pyplot as plt
import random
fig = plt.figure(figsize=(16,8))
fig.add_subplot(121)
s = 0
sList = [0] # 距离的列表
# 坐标x,y.
direction = ["北","南","东","西"]
x,y = (0,0)
xList = [0] # x坐标
yList = [0] # y坐标
for i in range(100000-1):
    stepDirection = random.choice(direction)
    if stepDirection == "北":
        y += 1
    elif stepDirection == "南":
        y -= 1
    elif stepDirection == "东":
        x += 1
    else:
        x -= 1
    s = (x**2 + y**2) ** 0.5
    sList.append(s)
    xList.append(x)
    yList.append(y)
plt.plot(list(range(0,100000)),sList)
plt.xlabel("Time")
plt.ylabel("Distance")
fig.add_subplot(122)
plt.plot(xList,yList)
plt.xlabel("X")
plt.ylabel("Y")
plt.show()