刚开始学，很多函数还不会，只会一些基本算法，所以还请各位程序简单化😂

代码如下，如有帮助，请采纳一下，谢谢。

#include <stdio.h>
void main()
{
    int ring[9]={1,2,3,4,5,6,7,8,9};
    int i,j,k,p,subs,sum;

    
    for (i=0;i<9;i++)
    {
        sum = 0;
        j = ring[i] * 10 + ring[(i+1)%9];
        sum += j;
        k = ring[(i+2)%9] * 100 + ring[(i+3)%9] * 10 + ring[(i+4)%9];
        sum += k;
        p = ring[(i+5)%9] * 1000 +ring[(i+6)%9] * 100 + ring[(i+7)%9] * 10 + ring[(i+8)%9];
        sum += p;
        if(sum%77==0)
            printf("%d + %d + %d = %d\n",j,k,p,sum);
    }
    
}

#include<stdio.h>

int mod9(int x)
{
    return x % 9;
}

int main()
{
    int ring[9] = { 1,2,3,4,5,6,7,8,9 }, st[9];
    int i,j, num1, num2, num3;
    for (i = 0; i < 9; i++)
    {
        num1 = ring[mod9(i)] * 10 + ring[mod9(i + 1) % 9];
        num2 = ring[mod9(i + 2)] * 100 + ring[mod9(i + 3)] * 10 + ring[mod9(i + 4)];
        num3 = ring[mod9(i + 5)] * 1000 + ring[mod9(i + 6)] * 100 + ring[mod9(i + 7)] * 10 + ring[mod9(i + 8)];
        st[i] = num1 + num2 + num3;
    }
    printf("所有和如下：\n");
    for (j = 0; j < 9; j++)
    {
        printf("%d\t", st[j]);
    }
    printf("\n和能被77整除的如下：\n");
    for (j = 0; j < 9; j++)
    {
        if (st[j] % 77 == 0)
            printf("%d\t", st[j]);
    }
    return 0;
}

自己上机调试一下吧

#include <stdio.h>
main ()
{
    int ring[9]={1,2,3,4,5,6,7,8,9}, st[9];
    int i, j, k, p, subs, sum;

    for(i=0;i<9;i++){
        sum=0;
        for (j=0;j<3;j++){
            subs=0;
            for(k=0;k<j+2;k++){
                p=i+j+k;
                if(p>=9){
                    p=0;
                }
                subs *=10;
                subs +=ring[p];
            }
            sum += subs;
        }
        st[i]=sum;
        if (sum%77==0){
            printf("sum is %s\n", sum);
        }
    }
}