在PHP中仅比较两个日期与月份和年份

Let me explain the scenario.

1. I have "Month(Any month from 01 TO 12)" and "Year(For Example 17 for 2017" in my local variables.

2. I want to compare it with Current Month and Year.

.

    $month = 04;
    $year = 17;
    if ($month.'-'.$year > current month & year)
    {
     echo "not expired";
    }
    else
    {
     echo "expired";
    }

3. For example:

$old_month = 03;  // March
$old_year = 17;   // 2017

$new_month = 05;  // May
$new_year = 17;   // 2017
//how to compare and determine which month&year is old one or new one ?

Searched a lot in google and SO posts, but couldn't find any solution. Please help me.

NB: I have only month and year in my hand to compare it with current month and year.

Atlast the following code worked fine for me.

$currentDate=date('d/m/Y'); // taking current date

$expirationDay = 31;
$expirationMonth = 12;
$expirationYear = 2017;

$date2 = $expirationYear.'-'.$expirationMonth.'-'.$expirationDay;
$date2 = date_create($date2);
$date2 = date_format($date2,"d/m/Y");

if($currentDate <= $date2)
{
  echo "not expired";
}
elseif($currentDate > $date2)
{
  echo "expired";
}

@Praveen George i hope you want to do it like below try this with date():

<?php
$searchingDate = '05-17'; // your variable which contain month and year
if($searchingDate == date("m-y")){ // date("m-y") return current month and year in format like('05-17) if both are equal then it match 
    echo "match";
}
else{
    echo "did not match";
} 

Use DateTime() to compare dates to each other. It's cleaner and easier to read as DateTime obejcts are comparable.

I used DateTime::createFromFormat since the dates you have from the API aren't going to be in a standard format for PHP and this makes it easier for PHp to handle.

$date = \DateTime::createFromFormat('my', $month.$year);
$now  = new \DateTime('midnight');
if ($date > $now) { 
    echo "not expired"; 
} else { 
    echo "expired"; 
}