日期（“M”）; 返回本月的以下结果...“02”

date("m"); returns the following result for this month... "02"

That is fine and dandy, but the problem is, I need to change 02 into February, and not by changing it to date("F");

I need to use the date function to convert the supplied number of 02 into February, is there a way of going about this logically without a bunch of if/else statements??

While date('F') would be preferred:

$monthnames = array(
  '01'=>'January',
  '02'=>'February',
  '03'=>'March'
); // and so on...

echo $monthnames[date("m")];

EDIT Adjusting to hitherto unspecified requirement:

$ts = mktime (0, 0, 0, date("m"), 1, date("Y"));

doc: http://us2.php.net/manual/en/function.mktime.php

<?php
$convertIntegerToMonth = array(
    1 => 'January',
    2 => 'February',
    3 => 'March',
    ...
);

$number = 2;
echo $convertIntegerToMonth[(int)$number];
?>

Forget those arrays! What about localization?

This will convert "02" to "February"

<?php
$month = date("m");    // "02"
$newstr = date("F", mktime(0, 0, 0, $month));   // "February"
?>

http://us2.php.net/manual/en/function.mktime.php

A simple way to do it:

date('F', strtotime("2000-$month-01"))

This code is working properly:

<?php 
    $year = 2016;
    $month = 02;
    echo date("M", mktime(null, null, null,$month+1, null, $year));
?>