I need help in solving this issue in php array_diff
. can anyone reslove this for me please.
first array
$array1 = array( [0]=> array( [id]=>1 [name]=>n1)
[1]=> array( [id]=>2 [name]=>n2)
[2]=> array( [id]=>3 [name]=>n3)
)
second array
$array2 = array( [0]=> array( [id]=>1 [name]=>n1)
)
output should look like
$outarray =array(
[0]=> array( [id]=>2 [name]=>n2)
[1]=> array( [id]=>3 [name]=>n3)
)
Many ways to do this, here's a functional one explicitly comparing the 'id'
keys:
$ids = array_map(function ($i) { return $i['id']; }, $array2);
$outarray = array_filter($array1, function ($i) use ($ids) {
return !in_array($i['id'], $ids);
});
More beginner friendly implementation, doing the same thing:
$ids = array();
foreach ($array2 as $value) {
$ids[] = $value['id'];
}
$outarray = array();
foreach ($array1 as $value) {
if (!in_array($value['id'], $ids)) {
$outarray[] = $value;
}
}
Are you missing $
s in front of variables? You can use this way:
$outarray[] = $array1;
$outarray[] = $array2;