输出mysql结果的问题

I create a form to register company and insert into DB. also created a form to insert each company cost and sell price. after all this has been inserted in DB, i try to output it on table but it was showing the company id instead of name... please bellow illustrate better

company DB

|id | company_name |
|1  | Oliva Ltd    |
|2  | Bone Mill    |

comp_product DB

|id | company_id   | cp     | sp    |
|3  | 2            | 20000  | 18000 |
|4  | 1            | 3000   | 100   |

The help I need is to output all data from comp_product DB by representing the company_id with their company_name from company DB.

Ouput Table

| company_id   | cp     | sp    |
| Bone Mill    | 20000  | 18000 |
| Oliva Ltd    | 3000   | 100   |

i tried bellow code, but i was showing only one row.

<table>
                          <thead>
                          <tr>
                              <th>company_id</th>
                              <th>cp</th>
                              <th>sp</th>
                          </tr>
                          <?php 

                          $result = mysql_query("SELECT * FROM comp_product ORDER BY id DESC");
                                while($row = mysql_fetch_array($result))
                                {
                                    $result = mysql_query("SELECT * FROM company WHERE id ='".$row['company_id']."'");
                                            while($rowz = mysql_fetch_array($result))
                                                { $name = $rowz['company_name']; }
                                    ?>
                          <tr>
                              <td><?php echo $name ?></td>
                              <td><?php echo $row['cp'] ?></td>
                              <td><?php echo $row['cp'] ?></td>
                          </tr>
                          <?php 
                                }
                                ?>
                      </table>

Show can I do this. Thanks for understanding

You need a JOIN query

SELECT `company`.`company_name`, `comp_product`.`cp`, `comp_product`.`sp`
FROM `company`
LEFT JOIN `comp_cp`
ON `company`.`id` = `comp_product`.`company_id`

You do not need two queries, you can just loop through the results of one. If you need to limit this to one company you can add a WHERE clause.

In addition you need to stop using mysql_* functions. These extensions have been removed in PHP 7. Learn about prepared statements for PDO and MySQLi and consider using PDO, it's really pretty easy.

Try this

 "SELECT company.company_name as company_id,comp_product.cp 
 ,comp_product.sp  FROM company inner join comp_product on 
 company.id = comp_product.company_id
 ORDER BY company.id DESC"

You will get desired result .

You need to use this query to properly show the data:

mysql_query ("SELECT company.company_name as company_id,comp_product.cp 
 ,comp_product.sp  FROM company where 
 company.id = comp_product.company_id
 ORDER BY company.id DESC");

The problem with your code outputting one row is simply because you're reusing the $result variable for both queries.

The name query result overwrites the price query.

Your code looks like this right now:

$result = mysql_query("SELECT * FROM comp_product ORDER BY id DESC");
while($row = mysql_fetch_array($result)){

    $result = mysql_query("SELECT * FROM company WHERE id ='".$row['company_id']."'");
    while($rowz = mysql_fetch_array($result)){ 

      $name = $rowz['company_name']; 
}

Change it to:

$result = mysql_query("SELECT * FROM comp_product ORDER BY id DESC");
while($row = mysql_fetch_array($result)){

    $name_query_result = mysql_query("SELECT * FROM company WHERE id ='".$row['company_id']."'");
    while($rowz = mysql_fetch_array($name_query_result)){ 

      $name = $rowz['company_name']; 
}