There are two tables. One table contains player information, like name and rank. The other table contains game substitution information.
the Output should look like this:
Rank| Player Name | Period 1 position | Period 2 Position| Period 3 Position |
Player Table Sample
|ID| Name | Rank |
|1 | Fred | 10 |
|2 | Dan | 12 |
|3 | Mike | 15 |
Position Table sample
|ID| Game_ID | Player_ID | Period | Position |
|1 | 12 | 1 | 1 | Striker Right|
|2 | 12 | 1 | 2 | Mid Center |
|3 | 12 | 2 | 1 | Striker Left |
Below is the code to get it out of MySQL
I've tried various ways transform the returned data set.
$players_sql = "SELECT position.id as position_id,
player.rank,
player.first_name,
position.period,
position.position
FROM player
INNER JOIN position
on player.id = position.player_id
ORDER BY player.rank, position.period;";
if ($result = $mysqli->query($players_sql)) {
// printf("Select returned %d rows.
", mysqli_num_rows($result));
/* fetch associative array */
while ($row = $result->fetch_assoc()) {
$subs[$row["position_id"]] = [
"rank" => $row["rank"],
"first_name" => $row["first_name"],
"period" => $row["period"],
"position" => $row["position"]
];
}
mysqli_free_result($result);
}
// collapse players This works
foreach ($subs as $sub) {
$players_by_rank[$sub["rank"]] = $sub["first_name"];
}
Later on the data is data is displayed in a form a user can submit. The code below does NOT match the code above. The code below used static defined arrays with pre-filled data that did not come from the database. It provides a way to visualize what the output needs to be. In the code example below there are a total of 4 periods that go into 4 columns and a summary column at the end. There must be an easy way to flatten this data!
<?php
for ($sub = 1; $sub < $sub_info . length; $sub++) {
?>
<tr>
<td><?php echo $sub_info[sub] ?></td>
<td><input type = "text"
name = "p<?php echo $player; ?>"
value = "<?php echo $names[$player - 1]; ?>"
id = "p<?php echo $player; ?>" ></td>
<?php
for ($period = 1; $period < $periods + 1; $period++) {
?>
<td>
<div class="form-group">
<select onchange="calTotals(<?php echo $player . ',' . $period; ?>)"
id="<?php echo "p{$player}p{$period}"; ?>"
name="<?php echo "p{$player}p{$period}"; ?>">
<?php
$output = "";
for ($i = 0; $i < $players_on_field + 1; $i++) {
$output = "<option";
if ($i == 0) {
$output .= ' selected';
}
$output .= ">$i</option>";
echo $output;
}
?>
</select>
</div>
</td>
<?php } ?> <!-- Periods -->
<td><!-- total periods in game using JavaScript -->
<input type="text"
name="<?php echo "periods{$player}"; ?>"
id="<?php echo "periods{$player}"; ?>">
</td>
</tr>
<?php } ?> <!-- players -->
You can use join to connect the tables, one instance of the players table, and three of the positions (one per period)
SELECT pl.rank, pl.name,
po1.position as period_1_position,
po2.position as period_2_position,
po3.position as period_3_position from
player as pl
inner join position as po1 on pl.id = po1.player_id and po1.period=1
inner join position as po2 on pl.id = po2.player_id and po2.period=2
inner join position as po3 on pl.id = po3.player_id and po3.period=3