I need to find the number of records that are greater than a specific float and find the group of data that repeat the most. For example, I have the data below and I need to find how many entries have values > 4.
1.5
1.7
4.5
4.7
4.8
1.4
4.5
4.9
In the above data the longest continuous repetition of values greater than 4 is 4.5,4.7,4.8. Therefore the total I would like returned should be 3. As you can see the pattern breaks after 4.8 since the number is 1.4 above. Is there a way to identify this pattern?
Try this, I have used here an array:
$arr = array(
0 => '1.5',
1 => '1.7',
2 => '4.5',
3 => '4.7',
4 => '4.8',
5 => '1.4',
6 => '4.5',
7 => '4.9'
);
$chk_val = 4; // value which is checking
$cnt = 0;$inc = 0;
foreach ($arr as $i => $val) {
if ($val > $chk_val) {
$inc++;
if ($inc > $cnt) { $cnt = $inc;}
} else {
$inc = 0;
}
}
echo $cnt;
try this
$n = 4; // number to check
$count = 0;
$max = 0;
$ele = array(1.5, 1.7, 4.5, 4.7, 4.8, 1.4, 4.5, 4.9);
for ($i = 0; $i < count($ele); $i++) {
if ($ele[$i] >= $n) { // check for greater element than given number
$count++; // increase consecutive counter variable
$arr[$max] = $count; //save continues max counter to array
} else {
$count = 0; //reset consecutive counter
$max++;
}
}
echo max($arr);
Quick and dirty...
function findNums($nums, $min = 4) {
$groups = array();
$groupcounts = array();
$groupindex = 0;
foreach($nums as $num) {
if($num > $min) {
$groups[$groupindex][] = $num;
if(array_key_exists($groupindex, $groupcounts)) {
$groupcounts[$groupindex]++;
} else {
$groupcounts[$groupindex] = 1;
}
} else {
$groupindex++;
}
}
return array($groupcounts, $groups);
}
// $your_numbers is your list
$nums = array_map('trim', explode("
", $your_numbers));
$result = findNums($nums);
$counts = $result[0];
$maxcount = max($counts);
$groups = $result[1];
echo "max count is ".$maxcount." with values:
";
$key = array_search($maxcount, $counts);
var_dump($groups[$key]);