如何使用PHP将http_build_query结果显示一页到另一页？

I am able to display records on same page but i have to display record one page to another page.I have seen many examples but can't quite get it right though.Would you please help me in this? one.php

$ids = $row["ID"];
$username = $row["Name"];
$search_d = array(
    'id'       => $ids, 
    'username' => $username,
);
$search_details = http_build_query($search_d);
header('Location: index.php?$search_details=1');

second.php

if(!empty($_GET['$search_details'])):
$name = $_GET['$search_details'];
print_r($name);
echo '<script>
setTimeout(function() {
    swal({
        title: "details done",
        type: "success",
        timer: 1500
    });
}, 1000);
</script>';
endif; 

You didn't concatenate the $search_details variable in the argument supplied to header.

$ids = 1;
$username = 'hassan';
$search_d = array(
    'id'       => $ids, 
    'username' => $username,
);
$search_details = http_build_query($search_d);
header('Location: index.php?' . $search_details);

on second page you have to do like that .

echo $_GET['id'];
echo $_GET['username'];

you dnt need to get search_details variable . This should work as you expect.

Where to begin...

In one.php:

header('Location: index.php?$search_details=1');

You're using $search_details within single quotes, meaning the variable will not be used. This will literally be the string index.php?$search_details=1.

$search_details = http_build_query($search_d);

This will build a query string like ids=value&name=value. Thus having a =1 after it doesn't make any sense.

In second.php:

If you correct one.php, you should be able to access $_GET['name'] and $_GET['ids']. $search_details is again in single quotes which makes little sense and that variable has no context in second.php.

To me, it seems like you have a lot of learning to do still, you should not be on Stackoverflow or building your own code yet, but reading and following guides.