从根文件夹中获取映像文件的名称。 文件夹的名称是上传

I am trying to get the name of a particular image file that has already been uploaded, not the one being uploaded in the folder to delete the file.

I have looked up all over google. Please help me. It is the last increment i have to make before the end of the day.

I do have the imageurl as http://localhost/public_html/upload/123.jpeg I have found this as my answer to delete the file but i do not know how to extract the file name

unlink($imagePath . $file_name);

Thank you

You can extract a file name from a path using basename like this:

 basename($imagePath); // output: 123.jpeg

or without the extension:

basename($imagePath, ".jpeg"); // output: 123

<?php
$path = "index.php"; //type file path with extension
$title = basename($path,".php"); // get only title without extension /remove (,".php") if u want display extension
echo $title;
?>

Try it with two way..

First : base_path

unlink(base_url("uploads/".$image_name));

getcwd : Some times absolute path not working.

unlink(getcwd()."/uploads/".$image_name);