表单提交打开一个弹出框？

I have a form and when submit im passing those data to another form. When i click on submit button i want to open form action in popup window . pls advice

  <form name="send_message" id="send_message" action="/user/message/"  role="form" method="post" accept-charset="UTF-8">
<input value="" id="email" name="email[]">
<button id="merge" name="status" value="message"  >
                <Send Message</button></form>

I want to open "/user/sendmessage/" in a popup when submit clicks?please advice.

   $(document).ready(function () {


        $('form').on('submit', function (e) {

            e.preventDefault();

            $.ajax({
                type: 'post',
                url: "/user/message/",
                data: $('form').serialize(),
                success: function (data) {
                    var emails = $('#email').val();

                }
            });
        })

here what i tried so far, im beginner pls advice how to proceed