检查数组键的范围是否为数字

I'm looking to loop through a an array and check whether the values are numbers.

for example

$rowdata is a mutltidimensional array

if (!is_int($rowData[0][0]||$rowData[0][1]||$rowData[0][2]) {
echo the value which is not a integer

}

Just for information, i already have the loop working it how i could achieve the above

EDIT:

Your if(!is_int($rowData[0][0]||$rowData[0][1]||$rowData[0][2])) is wrong. you have to split the parameter up like this:

if(!is_int($rowData[0][0]) || is_int_($rowData[0][1]) || is_int($rowData[0][2]))

use a nested foreach-loop

$rowData = array(array(1,2,"3"),array("asdf",1,"sadf"));

foreach($rowData as $key1=>$row1){
    foreach($row1 as $key2=>$row2){
        if(is_int($row2)){
            echo "\$rowData[$key1][$key2] is int".PHP_EOL;
        }
    }
}

output:

$rowData[0][0] is int
$rowData[0][1] is int
$rowData[1][1] is int

Snippet Example here

For a single array, this is a simple method to confirm that all are ints:

$a = [1, 2, 3, 'a', 4];
$allInt = array_reduce($a, function ($r, $i) { return $r && is_int($i); }, true);

So for your case:

if (!array_reduce($row[0], function ($r, $i) { return $r && is_int($i); }, true)) {
    // not all are integers
}

An alternative method, which also returns you the non-integer items:

array_filter($a, function ($i) { return !is_int($i); })

So:

if ($notInt = array_filter($row[0], function ($i) { return !is_int($i); })) {
    echo 'Not integers: ', join(', ', $notInt);
}