I have a form like so:
<select name="employment">
<option disabled="" selected="">-- What is your employment status --</option>
<option value="employed">Employed</option>
<option value="self_employed">Self Employed</option>
</select>
In PHP I am running through each of the $_POST variables and then checking if they have a value. If not I then add that field to the array for an error message.
The issue is that if I leave the default 'disabled' message selected nothing is passed through a post value so theres nothing for me to validate.
If I print_r my $_POST variable then it contains no 'employment' field unless I select an option.
How can I solve this?
<select name="employment">
<option disabled selected>-- What is your employment status --</option>
<option value="employed">Employed</option>
<option value="self_employed">Self Employed</option>
</select>
disabled attribute
Syntax:
<select disabled>
Not
<select disabled="">
In case of XHTML, syntax differs like
<select disabled="disabled">
hidden attribute
So, If you want to validate it. Use hidden
in option.
<select name="employment">
<option hidden>-- What is your employment status --</option>
<option value="employed">Employed</option>
<option value="self_employed">Self Employed</option>
</select>
When, nothing got selected, then it will output as -- What is your employment status --
<?php
echo $Employment=$_POST['employment'];
?>
Output: -- What is your employment status --
So, Now you can easily use your validation in dropdown
For more info, click disabled attribute - W3 Schools
Try this:
<select name="employment">
<option disabled="" selected="" value ="">-- What is your employment status --</option>
<option value="employed">Employed</option>
<option value="self_employed">Self Employed</option>
</select>
PHP:
if(empty($_POST['employment'])){
return false;
}else {
// I got value;
}