Problem: Multiple forms on the same page, but only the first one is being submitted.
Tried the following: Equating the data-ids of submit button and Form inorder to submit the clicked form (No Luck) Dynamic form creation using Javascript.(disbanded that idea after a few tries since it was on a deadline)
Usecase The number of forms depends on the User. If there is just one comment from him, the form submits, while if there are say 4 forms, only the first one will submit.
Javascript:
$(function() {
$(".submit").click(function() {
var data_id = $(this).data('id');
var form_id = $(this.form).data('id');
if (parseInt(data_id, 10) == parseInt(form_id, 10)) {
var commentid = document.getElementByID('commentid');
alert(commentid + formid);
} else {
alert("10");
}
});
});
PHP code:
if($comment['Comment_Username'] ==$this->getUser()->getName())
{$output .='div class="panel" data-class="'.$comment['CommentID'].'">';
$output .='<form class="form" action="" method="post" data- id="'.$comment['CommentID'].'">';
$output .='<textarea name="edit_text' class="box" rows="2" cols="1">'.$this->getCommentText($comment['Comment_Text']).'</textarea>';
$output .='<input name="commentid" type="hidden" id="commentid" value="'.$comment['CommentID'].'"/>';
$output .='<input type="button' data-id="'.$comment['CommentID'].'" class="submit" value="submit"/>';
Any help would be greatly appreciated. Thanks in advance
Wrong quote used here
$output .='<textarea name="edit_text" class="box" rows="2" cols="1">'.$this->getCommentText($comment['Comment_Text']).'</textarea>';