如何将特定数据库记录发送到其他文件

My question is regarding the ability to update a certain record by choosing a single record from a table and going to that selected record in another page with the full data. I know I would have to create another file with all of the input fields I need, but my question is how do I get there and send over the data info that I selected, then how do I echo out that information and allow the record to be updated?

Let's say I have a table called "Products" that looks like this:

ID Name Amount

1 Shoes $10 Edit

2 Hats $5 Edit

If I click the "Edit" Button next to "Shoes" I want to go to a different page which allows me to edit all of the information for that record selected.

  <form method="POST">
   <input name="first" placeholder="First Name">
   <input name="last" placeholder="Last Name">
   <input name="product" placeholder="Product">
   <button name="add" type="submit">Add</button>
</form>
</div>
<hr>
<table>
<thead>
   <tr>
      <th>ID</th>
      <th>Name</th>
      <th>Amount</th>
      <th></th>
   </tr>
</thead>
<tbody>
   <?php
      $stmt = $dbc->query("SELECT * FROM users");
      $stmt->setFetchMode(PDO::FETCH_ASSOC);

      while($row = $stmt->fetch()) {
      ?>
   <form method="POST">
      <tr>
         <td><?php echo $row['id'];?></td>
         <td><?php echo $row['name'];?></td>
         <td><?php echo $row['amount'];?></td>
         <td><button name="edit" type="submit">Edit</button></td>
      </tr>
   </form>
   <?php } ?>
</tbody>

You can send your form data to next page using hidden field as

<form method="POST" action="edit_page.php">// add action here
        <tr>
            <td><?php echo $row['id'];?></td>
            <td><?php echo $row['name'];?></td>
            <td><?php echo $row['amount'];?></td>
            <input name="name" type="hidden" value="<?php echo $row['name'];?>">
            <input name="id" type="hidden" value="<?php echo $row['id'];?>">
            <input name="amount" type="hidden" value="<?php echo $row['amount'];?>">
            <td><button name="edit" type="submit">Edit</button></td>
        </tr>
    </form> 

And in edit_page.php use

$name=$_POST['name'];
$id=$_POST['id'];
$amount=$_POST['amount'];
<form method="POST" action="other_page.php">
        <tr>
           <input type="hidden" name="id" value="<?php echo $row['id'] ?>" />
           <input type="hidden" name="name" value="<?php echo $row['name'] ?>" />
           <input type="hidden" name="amount" value="<?php echo $row['amount'] ?>" />

            <td><?php echo $row['id'];?></td>
            <td><?php echo $row['name'];?></td>
            <td><?php echo $row['amount'];?></td>
            <td><button name="edit" type="submit">Edit</button></td>
        </tr>
</form> 

And then in other_page.php:

<?php

    $stmt = $dbc->query("SELECT * FROM products WHERE `id`=".$_POST['id'].";");
    $stmt->setFetchMode(PDO::FETCH_ASSOC);
    ?>


    <form method="POST" action="<?php echo htmlspecialchars($_SERVER['PHP_SELF']) ?>">
        <input type="text" name="id" value="<?php echo $row['id'] ?>" />
        <input type="text" name="name" value="<?php echo $row['name'] ?>" />
        <input type="text" name="amount" value="<?php echo $row['amount'] ?>" />
        <button name="update" type="submit">Edit</button>
    </form>

    <?php
    if (isset($_POST['update'])){ // if the update button is clicked
        // write your update query here, with $id = $_POST['id'] and so on...
    }