PHP preg_match_all - 正则表达式和breakline

Here's me function with regexp:

preg_match_all('|<span class=\"Menu1\">(.*?)</td>|U',$contents,$wynik2);

It works with:

  <tr>
        <td width="30%" ><span class="Menu"> Nazwa zawdsdu: </td>
        <td width="70%"> <span class="Menu1">PRACOWNIK BARU  </td>
        </tr>

but it doesn't work with:

<td width="70%"> <span class="Menu1">PRACA W MC DONALDS PRACE PORZĄDKOWE, PRZYJĘCIE DOSTAWY
WYMAGANA KSIĄŻECZKA SANEPIDOWSKA, CHĘCI DO PRACY
KONTAKT TEL. 794295401 </td>

I've got empty array. I think its caused by 'new line'. How can i fix it?

Add the s modifier to the end of your regex.

Sorry, but I felt obliged to give a DOMDocument example:

$d = new DOMDocument;
$d->loadHTML($html);

$xpath = new DOMXPath($d);

foreach ($xpath->query('//span[@class="Menu1"]') as $node) {
    echo $node->nodeValue, PHP_EOL;
}

Applied to your scraper (redacted the url and post fields)

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, 'http://redacted');
curl_setopt($ch, CURLOPT_POSTFIELDS, 'redacted');
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);

$d = new DOMDocument;
libxml_use_internal_errors(true);

$d->loadHTML(curl_exec($ch));
libxml_clear_errors();

$xpath = new DOMXPath($d);

foreach ($xpath->query('//span[@class="Menu1"]') as $node) {
    echo $node->nodeValue, PHP_EOL;
}