有没有哪位会这个呀？不会

定义一个名为Student的类，init方法通过学号，姓名，课程成绩（字典数据类型，三门以上）描述学生，实例方法score求课程的平均成绩并输出学生的个人信息与平均成绩。实例2个学生对象,并输出相关信息。
测试数据：A12345691,Liming,{Math:85,Chinese:80,English:99}; A12345692 Wangfang,{Math:75,Chinese:90,English:88,CPrograme:89};

class Student:
    def __init__(self, student_id, name, grades) -> None:
        self.student_id = student_id
        self.name = name
        self.grades = grades

    def score(self):
        avg = sum(self.grades.values()) / len(self.grades)
        print('学号:', self.student_id)
        print('名字:', self.name)
        print('平均成绩:', avg)


if __name__ == '__main__':
    s1 = Student('A12345691', 'Liming', {'Math': 85, 'Chinese': 80, 'English': 99})
    s2 = Student('A12345692', 'Wangfang', {'Math': 75, 'Chinese': 90, 'English': 88, 'CProgramme': 89})
    s1.score()
    print()
    s2.score()

class Student:
    def __init__(self, id, name, scores):
        self.id = id
        self.name = name
        self.scores = scores

    def score(self):
        avg_score = sum(self.scores.values()) / len(self.scores)
        print(f"学生信息：\n学号：{self.id}\n姓名：{self.name}\n课程平均成绩：{avg_score:.2f}\n")

student1 = Student("A12345691", "Liming", {"Math":85, "Chinese":80, "English":99})
student2 = Student("A12345692", "Wangfang", {"Math":75, "Chinese":90, "English":88, "CPrograme":89})

student1.score()
student2.score()

刚好符号你的需求，你试试看呢？