使用quartus ii,vhdl描述法
完成一个串行序列信号发生器、接收器
一、设计并实现一个串行信号发生器,具体要求如下:
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https://www.yjbys.com/biyelunwen/fanwen/zidonghua/368686.html
该回答通过自己思路及引用到GPTᴼᴾᴱᴺᴬᴵ搜索,得到内容具体如下:
以下是一个可能的串行信号发生器和接收器的设计,使用了VHDL语言和Quartus II工具。
串行信号发生器的设计:
library ieee;
use ieee.std_logic_1164.all;
use ieee.numeric_std.all;
entity serial_generator is
port(
clk : in std_logic;
btn : in std_logic;
sw : in std_logic_vector(7 downto 0);
scl_out : out std_logic;
sda_out : out std_logic;
ld : out std_logic_vector(7 downto 0)
);
end entity;
architecture rtl of serial_generator is
signal cnt : integer range 0 to 19999999 := 0;
signal counter : integer range 0 to 7 := 0;
signal data : std_logic_vector(7 downto 0) := (others => '0');
signal start : std_logic := '0';
signal stop : std_logic := '0';
signal sda : std_logic := '1';
begin
-- 时钟分频,将100MHz分频为100Hz
process(clk)
begin
if rising_edge(clk) then
if cnt = 999999 then
cnt <= 0;
else
cnt <= cnt + 1;
end if;
end if;
end process;
-- 按键去抖
process(clk, btn)
begin
if rising_edge(clk) then
if btn = '1' then
start <= '1';
counter <= 0;
else
start <= '0';
end if;
end if;
end process;
-- 产生串行时钟信号
process(cnt)
begin
if cnt = 0 then
scl_out <= not scl_out;
ld(0) <= scl_out;
if scl_out = '1' then
if start = '1' then
sda <= '0';
start <= '0';
elsif counter < 8 then
sda <= sw(counter);
counter <= counter + 1;
elsif counter = 8 then
sda <= '1';
counter <= 9;
else
sda <= '1';
stop <= '1';
end if;
end if;
end if;
end process;
-- 输出串行数据
sda_out <= sda;
end architecture;
串行信号接收器的设计:
library ieee;
use ieee.std_logic_1164.all;
use ieee.numeric_std.all;
entity serial_receiver is
port(
clk : in std_logic;
scl_in : in std_logic;
sda_in : in std_logic;
d : out std_logic_vector(7 downto 0);
disp : out std_logic_vector(3 downto 0);
ld : out std_logic_vector(15 downto 0)
);
end entity;
architecture rtl of serial_receiver is
signal cnt : integer range 0 to 19999999 := 0;
signal counter : integer range 0 to 7 := 0;
signal data : std_logic_vector(7 downto 0) := (others => '0');
signal start : std_logic := '0';
signal stop : std_logic := '0';
signal sda : std_logic := '1';
begin
-- 时钟分频,将100MHz分频为10Hz或100Hz
process(clk)
begin
if rising_edge(clk) then
if cnt = 99999999 then
cnt <= 0;
else
cnt <= cnt + 1;
end if;
end if;
end process;
-- 接收串行数据
process(cnt)
begin
if cnt = 0 then
if scl_in = '0' then
if start = '0' then
start <= '1';
counter <= 0;
elsif counter < 8 then
data(counter) <= sda_in;
counter <= counter + 1;
elsif counter = 8 then
stop <= '1';
counter <= 9;
else
stop <= '1';
end if;
else
start <= '0';
stop <= '0';
counter <= 0;
end if;
end if;
end process;
-- 输出数据
d <= data;
if ld(7) = '1' then
if d(7) = '1' then
disp <= "011";
ld(15 downto 8) <= "00000001";
ld(7 downto 0) <= data;
else
disp <= "000";
ld(15 downto 8) <= "00000000";
ld(7 downto 0) <= (others => '0');
end if;
else
disp <= "000";
ld(15 downto 0) <= (others => '0');
end if;
end architecture;
这两个设计都需要在Quartus II中编译、综合、生成比特流文件,并下载到实验板上进行测试。同时,还需要在实验板上连接SW7~SW0、BTN3、LD0、LD7、94脚和95脚等接口,以便与外界进行数据交互。
如果以上回答对您有所帮助,点击一下采纳该答案~谢谢
你好,引用chatgpt部分指引作答,这个project1实现一个串行信号发生器
library ieee;
use ieee.std_logic_1164.all;
entity serial_generator is
port (
SW : in std_logic_vector(7 downto 0); -- parallel data input
BTN : in std_logic; -- start button
CLK : in std_logic; -- system clock (100Hz)
LD : out std_logic_vector(7 downto 0); -- LED display
SCL : out std_logic; -- serial clock output (94 pin)
SDA : out std_logic -- serial data output (95 pin)
);
end entity serial_generator;
architecture rtl of serial_generator is
type state_type is (idle, start, send, stop); -- state machine enumeration
signal current_state, next_state : state_type; -- state machine signals
signal counter : integer range 0 to 99; -- counter for serial clock generation
signal shift_reg : std_logic_vector(7 downto 0); -- shift register for parallel data output
begin
process (CLK, BTN)
begin
if BTN = '1' then -- reset the state machine and the counter when the button is pressed
current_state <= idle;
counter <= 0;
elsif rising_edge(CLK) then -- update the state machine and the counter on the rising edge of system clock
current_state <= next_state;
counter <= counter + 1;
if counter = 99 then -- reset the counter when it reaches the maximum value
counter <= 0;
end if;
end if;
end process;
process (current_state, SW, counter)
begin
case current_state is
when idle => -- idle state: do not send data,
SCL <= '1'; -- keep the serial clock and data high
SDA <= '1';
LD(0) <= '0'; -- turn off the LED display
LD(7) <= '0';
if counter = 0 then -- check the counter value to determine when to start sending data
next_state <= start; -- go to the start state
shift_reg <= SW; -- load the parallel data into the shift register
else
next_state <= idle; -- stay in the idle state
end if;
when start => -- start state: generate the start signal
SCL <= '1'; -- keep the serial clock high
SDA <= '0'; -- change the serial data from high to low
LD(0) <= '1'; -- turn on the LED display to indicate the serial clock
LD(7) <= '1'; -- turn on the LED display to indicate the serial data
if counter = 49 then -- check the counter value to determine when to send the first bit of data
next_state <= send; -- go to the send state
else
next_state <= start; -- stay in the start state
end if;
when send => -- send state: send the parallel data bit by bit
SCL <= not SCL; -- toggle the serial clock
SDA <= shift_reg(7); -- output the most significant bit of the shift register
LD(0) <= SCL; -- display the serial clock on the LED
LD(7) <= SDA; -- display the serial data on the LED
if counter = 49 then -- check the counter value to determine when to shift the register
shift_reg <= '0' & shift_reg(7 downto 1); -- shift the register right by one bit
if shift_reg = "00000000" then -- check if all bits have been sent
next_state <= stop; -- go to the stop state
else
next_state <= send; -- stay in the send state
end if;
else
next_state <= send; -- stay in the send state
end if;
when stop => -- stop state: generate the stop signal
SCL <= '1'; -- keep the serial clock high
SDA <= '1'; -- change the serial data from low to high
LD(0) <= '1'; -- turn on the LED display to indicate the serial clock
LD(7) <= '1'; -- turn on the LED display to indicate the serial data
if counter = 49 then -- check the counter value to determine when to go back to idle state
next_state <= idle; -- go to the idle state
else
next_state <= stop; -- stay in the stop state
end if;
end case;
end process;
end architecture rtl;
这个project2实现一个串行信号接收器,接收以上串行信
号发生器发送的信号
library ieee;
use ieee.std_logic_1164.all;
entity serial_receiver is
port (
CLK : in std_logic; -- system clock (10Hz or 100Hz)
RST : in std_logic; -- reset signal
SCL : in std_logic; -- serial clock input (94 pin)
SDA : in std_logic; -- serial data input (95 pin)
LD : out std_logic_vector(15 downto 0); -- LED display
DISP : out std_logic_vector(7 downto 0); -- seven-segment display
AN : out std_logic_vector(3 downto 0) -- seven-segment display selector
);
end entity serial_receiver;
architecture rtl of serial_receiver is
type state_type is (idle, receive, display); -- state machine enumeration
signal current_state, next_state : state_type; -- state machine signals
signal counter : integer range 0 to 99; -- counter for system clock division
signal clk_bps : std_logic; -- divided clock for serial data sampling
signal shift_reg : std_logic_vector(7 downto 0); -- shift register for serial data storage
signal start_flag, stop_flag : std_logic; -- flags for start and stop signals detection
begin
process (CLK, RST)
begin
if RST = '1' then -- reset the state machine and the counter when the reset signal is high
current_state <= idle;
counter <= 0;
elsif rising_edge(CLK) then -- update the state machine and the counter on the rising edge of system clock
current_state <= next_state;
counter <= counter + 1;
if counter = 99 then -- reset the counter when it reaches the maximum value
counter <= 0;
end if;
end if;
end process;
process (current_state, SCL, SDA, counter)
begin
case current_state is
when idle => -- idle state: do not receive data,
clk_bps <= '0'; -- keep the divided clock low
LD(15) <= '0'; -- turn off the LED display
AN <= "1111"; -- turn off the seven-segment display
DISP <= "00000000"; -- clear the seven-segment display data
if SCL = '1' and SDA = '0' then -- check if a start signal is detected
next_state <= receive; -- go to the receive state
shift_reg <= "00000000"; -- clear the shift register
start_flag <= '1'; -- set the start flag
else
next_state <= idle; -- stay in the idle state
start_flag <= '0'; -- clear the start flag
end if;
when receive => -- receive state: receive the serial data bit by bit
if counter = 0 then -- check the counter value to generate the divided clock
clk_bps <= '1'; -- set the divided clock high
elsif counter = 49 then
clk_bps <= '0'; -- set the divided clock low
end if;
if rising_edge(clk_bps) then -- sample the serial data on the rising edge of divided clock
shift_reg <= SDA & shift_reg(7 downto 1); -- shift the register left by one bit and input the serial data
if SCL = '1' and SDA = '1' then -- check if a stop signal is detected
next_state <= display; -- go to the display state
stop_flag <= '1'; -- set the stop flag
else
next_state <= receive; -- stay in the receive state
stop_flag <= '0'; -- clear the stop flag
end if;
else
next_state <= receive; -- stay in the receive state
end if;
when display => -- display state: display the received data on the seven-segment display
clk_bps <= '0'; -- keep the divided clock low
LD(15) <= shift_reg(7); -- display the D7 bit on the LED
AN <= not shift_reg(6 downto 4); -- select the seven-segment display according to D6-D4 bits
DISP <= to_bcd(shift_reg(3 downto 0)); -- convert the D3-D0 bits to BCD code and display on the seven-segment display
next_state <= idle; -- go back to the idle state after displaying
end case;
end process;
function to_bcd (bin : std_logic_vector(3 downto 0)) return std_logic_vector is -- a function to convert binary code to BCD code for seven-segment display
variable bcd : std_logic_vector(7 downto 0);
begin
case bin is
when "0000" => bcd := "00000001"; -- 0
when "0001" => bcd := "10011111"; -- 1
when "0010" => bcd := "00100101"; -- 2
when "0011" => bcd := "00001101"; -- 3
when "0100" => bcd := "10011011"; -- 4
when "0101" => bcd := "01001001"; -- 5
when "0110" => bcd := "01000001"; -- 6
when "0111" => bcd := "00011111"; -- 7
when "1000" => bcd := "00000001"; -- 8
when "1001" => bcd := "00001001"; -- 9
when others => bcd := "11111111"; -- blank
end case;
return bcd;
end function;
end architecture rtl;
以下答案由GPT-3.5大模型与博主波罗歌共同编写:
这是一道比较具体的数字电路设计题目,需要用到FPGA开发工具Quartus II和VHDL语言进行描述和实现。具体实现流程如下:
根据题目要求,设计出顺序逻辑电路,用以将并行输入信号转换为串行输出信号。实现步骤如下:
VHDL代码如下:
library IEEE;
use IEEE.std_logic_1164.all;
use IEEE.numeric_std.all;
entity generate_sd_serial is
port (
sw : in std_logic_vector(7 downto 0);
btn : in std_logic;
clk_100 : in std_logic;
sda : out std_logic;
scl : out std_logic;
ld7 : out std_logic);
end generate_sd_serial;
architecture sd_serial of generate_sd_serial is
type state is (idle, start, transmit_data, stop);
signal current_state: state;
signal data_count: integer range 0 to 7;
signal transmit_data_now: std_logic;
signal send_start: std_logic;
signal send_stop: std_logic;
signal time_out_sig: std_logic;
begin
process(clk_100, btn)
begin
if btn='1' then
current_state <= start;
data_count <= 0;
send_start <= '1';
send_stop <= '0';
elsif clk_100='1' and clk_100'event then
case current_state is
when idle =>
scl <= '1';
sda <= '1';
ld7 <= '0';
data_count <= '0';
send_start <= '0';
send_stop <= '1';
when start =>
if send_start = '1' then
scl <= '1';
sda <= '0';
if time_out_sig = 'Z' then
time_out_sig <= '0';
else
time_out_sig <= next_time_out;
end if;
else
current_state <= transmit_data;
end if;
when transmit_data =>
scl <= '0';
sda <= transmit_data_now;
if data_count = 7 then
current_state <= stop;
else
current_state <= transmit_data;
end if;
data_count <= data_count + 1;
when stop =>
scl <= '1';
sda <= '1';
ld7 <= '1';
if time_out_sig = 'Z' then
time_out_sig <= '0';
else
time_out_sig <= next_time_out;
end if;
if time_out_sig = '1' then
current_state <= idle;
else
current_state <= start;
send_start <= '1';
send_stop <= '0';
data_count <= 0;
end if;
end case;
end if;
end process;
next_time_out <= NOT time_out_sig;
with current_state select
transmit_data_now <=
sw(7) when transmit_data,
sw(6) when transmit_data and data_count = 1,
sw(5) when transmit_data and data_count = 2,
sw(4) when transmit_data and data_count = 3,
sw(3) when transmit_data and data_count = 4,
sw(2) when transmit_data and data_count = 5,
sw(1) when transmit_data and data_count = 6,
sw(0) when transmit_data and data_count = 7,
'0' when others;
scl <= '1' when send_start = '1' or send_stop = '1' else '0';
end sd_serial;
根据题目要求,设计出逆序逻辑电路,用以将串行输入信号转换为并行输出信号。实现步骤如下:
VHDL代码如下:
library IEEE;
use IEEE.std_logic_1164.all;
use IEEE.numeric_std.all;
entity receive_sd_serial is
port (
clk_10 : in std_logic;
clk_100 : in std_logic;
sda : in std_logic;
scl : in std_logic;
ld15 : out std_logic;
disp : out std_logic_vector(2 downto 0);
d : out std_logic_vector(7 downto 0));
end receive_sd_serial;
architecture sd_serial of receive_sd_serial is
type state is (idle, start, receive_data, stop);
signal current_state: state;
signal data_count: integer range 0 to 7;
signal receive_data_now: std_logic;
signal start_bit_received: std_logic;
signal stop_bit_received: std_logic;
signal display: std_logic;
signal d_value: std_logic_vector(3 downto 0);
begin
process(clk_100)
begin
if clk_100='1' and clk_100'event then
case current_state is
when idle =>
ld15 <= '0';
display <= '0';
disp <= "000";
data_count <= 0;
start_bit_received <= '0';
stop_bit_received <= '0';
current_state <= start;
when start =>
if scl = '1' and sda = '0' and not start_bit_received then
start_bit_received <= '1';
end if;
if scl = '0' and start_bit_received then
receive_data_now <= sda;
current_state <= receive_data;
end if;
when receive_data =>
if scl = '1' then
receive_data_now <= sda;
end if;
if scl = '0' then
data_count <= data_count + 1;
end if;
if data_count = 7 then
current_state <= stop;
end if;
when stop =>
if scl = '1' and sda = '1' and not stop_bit_received then
stop_bit_received <= '1';
end if;
if scl = '0' and stop_bit_received then
ld15 <= '1';
d_value <= std_logic_vector(to_unsigned(2#(d(3 downto 0)),4));
if d(7) = '1' then
disp <= "011";
display <= '1';
end if;
if d(6) = '1' then
disp <= "010";
display <= '1';
end if;
if d(5) = '1' then
disp <= "001";
display <= '1';
end if;
if d(4) = '1' then
disp <= "000";
display <= '1';
end if;
if d(3) = '1' then
disp <= "101";
display <= '1';
end if;
if d(2) = '1' then
disp <= "100";
display <= '1';
end if;
if d(1) = '1' then
disp <= "011";
display <= '1';
end if;
if d(0) = '1' then
disp <= "010";
display <= '1';
end if;
current_state <= start;
start_bit_received <= '0';
stop_bit_received <= '0';
data_count <= 0;
end if;
end case;
end if;
end process;
d(3 downto 0) <= d_value;
end sd_serial;
以上就是本题目的详细解答和VHDL代码。需要注意的是,本题是针对特定的硬件设备而定的,所以代码不能直接用于其他设备上,需要针对不同设备进行修改。
如果我的回答解决了您的问题,请采纳!
以下答案由GPT-4.5Plus大模型(语音)与博主A努力中.......共同编写:
根据要求,串行序列发生器和接收器的VHDL设计思路如下:
一、串行序列发生器:
vhdl
port(
SW: in std_logic_vector(7 downto 0);
LD: out std_logic_vector(1 downto 0);
SCL: out std_logic;
SDA: out std_logic
);
vhdl
process(CLK)
begin
if(BTN3'event and BTN3 = '1') then
SCL <= '1';
LD(0) <= '1';
wait for 2000ms;
for i in 0 to 7 loop
SDA <= SW(i);
wait for 2000ms;
end loop;
SCL <= '0';
end if;
end process;
二、串行序列接收器:
vhdl
port(
SCL: in std_logic;
SDA: in std_logic;
D: out std_logic_vector(7 downto 0);
LD: out std_logic_vector(15 downto 0)
);
vhdl
process(CLK)
begin
if(SCL'event and SCL = '1') then
D(i) <= SDA;
i <= i + 1;
elsif(SCL'event and SCL = '0') then
if(D(7) = '1') then
case D(6 downto 4) is
when "001" => DISP1 <= D(3 downto 0);
when "010" => DISP2 <= D(3 downto 0);
...
end case;
end if;
LD(15) <= D(7);
i <= 0;
end if;
end process;
以上就是根据要求完成串行序列发生器和接收器的VHDL设计思路。通过定义端口和进程,实现发生器产生数据和控制信号,接收器读取数据控制数码管显示。如果在实现的过程中遇到问题,请在CSDN提问,我将继续解答和讨论。