正则表达式，用于在带或不带id属性的标签之间获取字符串

I have a string like below. I want to write a preg_match_all() function to get 'one' and 'two'. What change have to be done to the expression below to get the desired result?

$featureTab = "<li>one</li><li id='someId'>two</li>";

I have tried below code.

preg_match_all('/(?<=\<li\>)(.*?)(?=\<\/li\>)/', $featureTab ,$matches);

But it just returns 'one'. as the pregx only considers strings between the li tag not with id. Help me with a regular expression that will return both one and two.

You can simply use below regex

<li.*?>(.*?)<\/li>

Over here

`<li.*?>` here `(.*)` is to capture all attributes of `li` and `?` is to if no attributes is defined or not even space count also

As both has different li structure

You can check it

Demo

Note: For HTML/XML parsing don't go for regex you can simply use DOMDocument for same

You can use this regex:

<li[^>]*>(.*?)<\/li>

$re = '/<li[^>]*>(.*?)<\/li>/';
$str = '<li>one</li><li id=\'someId\'>two</li>';

preg_match_all($re, $str, $matches, PREG_SET_ORDER, 0);

// Print the entire match result
var_dump($matches);

Check out the result here: https://3v4l.org/arFRq