python爬虫怎么对结果进行处理

import requests
from bs4 import BeautifulSoup

headers = {"User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:109.0) Gecko/20100101 Firefox/111.0"}
response =requests.get('https://movie.douban.com/chart', headers=headers)
html = response.text

soup = BeautifulSoup(html, "html.parser")
# print(soup)
all_titles = soup.findAll("div", attrs={"class": "pl2"})
for title in all_titles:
    all_name = title.find('a')
    for name in all_name:
        c = name.string
        d = c.replace(' ', '')
        e = d.replace('\n', '')
        print(e)

疾速追杀4/
杀神JohnWick4(港)/捍卫任务4(台)

杀死福顺/
格杀福顺/KillBoksoon

俄罗斯方块/
俄罗斯方块：版权之争

鲸/
庞然大物/我的鲸鱼老爸(台)

网络谜踪2/
人肉搜索2：失踪搜救(台)/人肉搜寻2(港)

断网/
断网24小时/CyberHeist

金爆行动/
玩命特攻：武演行动(台)/伙星行动：扭计特攻(港)

三线轮洄/
三线轮回

下一个素熙/
NextSohee/陰影下的她(台)

阿凡达：水之道/
阿凡达2/阿凡达2：水之道

代码下部分是我爬出来的电影排行榜结果。但是我只需要电影的第一个名字，斜杠后面的外文名字不需要，而且不需要中间的空行。有没有好心的老哥教教我，怎么处理爬出来的数据！

试试这个代码：

import requests
from bs4 import BeautifulSoup
import re

headers = {"User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:109.0) Gecko/20100101 Firefox/111.0"}
response = requests.get('https://movie.douban.com/chart', headers=headers)
html = response.text

soup = BeautifulSoup(html, "html.parser")
all_titles = soup.findAll("div", attrs={"class": "pl2"})
for title in all_titles:
    all_name = title.find('a')
    for name in all_name:
        c = name.string
        d = c.replace(' ', '')
        e = d.replace('\n', '')
        first_name = re.split('/', e)[0]  # 使用正则表达式将字符串按斜杠分割，并提取第一个名字
        if first_name:  # 跳过空字符串
            print(first_name)

你的代码有问题，find修改为findAll ,其次使用contents获取节点，可解析a标签本身的文本，而不包括其子节点的文本。代码：

import requests
from bs4 import BeautifulSoup
import re

headers = {"User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:109.0) Gecko/20100101 Firefox/111.0"}
response = requests.get('https://movie.douban.com/chart', headers=headers)
html = response.text

soup = BeautifulSoup(html, "html.parser")
all_titles = soup.findAll("div", attrs={"class": "pl2"})
for title in all_titles:
    all_name = title.findAll('a')
    for name in all_name:
        name = name.contents[0]
        name = re.sub('/','',name)
        name = name.strip()

        if name:  # 跳过空字符串
            print(name)

运行结果：

img