C语言程序设计 C语言

统计字符个数
能帮忙看看这个吗
有点小困难
根本不知道怎么写
帮帮我

用gets函数接收一行字符。或者用getchar()逐个字符接收，然后判断字符范围进行统计

#include <stdio.h>
int main()
{
    int letter = 0,black = 0,digit = 0,other = 0;
    char c;
    printf("Input 10 characters: ");
    while((ch=getchar()) != '\n')
    {
        if((ch >='a' && ch <='z') || (ch>='A' && ch<='Z'))
            letter++;
        else if(ch == ' ')
            black++;
        else if(ch>='0' && ch<='9')
            digits++;
        else
            others++;
    }
    printf("letter=%d,black=%d,digit=%d,other=%d",letter,black,digit,other);
}

供参考：

#include<stdio.h>
int main()
{
    char ch;
    int  i, letter = 0, digit = 0, blank = 0, other = 0;
    printf("Input 10 characters: ");
    for (i = 0; i < 10; i++)
    {
        ch = getchar();
        if ((ch >= 'a' && ch <= 'z') || (ch >= 'A' && ch <= 'Z'))
            letter++;
        else if (ch >= '0' && ch <= '9')
            digit++;
        else if (ch == ' ' || ch == '\n')
            blank++;
        else
            other++;
    }
    printf("letter=%d,blank=%d,digit=%d,other=%d", letter, blank, digit, other);
    return  0;
}