写出下面代码的输出结果，并进行代码输出分析
#include
using namespace std;
class BaseA
{
public:
BaseA(int a, int b);
~BaseA();
protected:
int m_a;
int m_b;
};
BaseA::BaseA(int a, int b) :m_a(a), m_b(b) {
cout << "BaseA constructor" << endl;
}
BaseA::~BaseA() {
cout << "BaseA destructor" << endl;
}
class BaseB {
public:
BaseB(int c, int d);
~BaseB();
protected:
int m_c;
int m_d;
};
BaseB::BaseB(int c, int d) :m_c(c), m_d(d) {
cout << "BaseB constructor" << endl;
};
BaseB::~BaseB() {
cout << "BaseB destructor" << endl;
}
class Derived :public BaseA, public BaseB {
public:
Derived(int a, int b, int c, int d, int e);
~Derived();
public:
void show();
private:
int m_e;
};
Derived::Derived(int a, int b, int c, int d, int e) :BaseA(a, b), BaseB(c, d), m_e(e) {
cout << "Derived constructor" << endl;
}
Derived::~Derived() {
cout << "Derived destructor" << endl;
}
void Derived::show() {
cout << m_a << "," << m_b << "," << m_c << "," << m_d << "," << m_e << endl;
}
int main() {
Derived obj(1, 2, 3, 4, 5);
obj.show()；
return 0;
}
BaseA constructor
BaseB constructor
Derived constructor
1,2,3,4,5
Derived destructor
BaseB destructor
BaseA destructor
代码输出分析如下：
首先创建了一个 Derived 类型的对象 obj，在创建过程中调用了 Derived 的构造函数。
在 Derived 构造函数中，首先调用 BaseA 的构造函数，输出 "BaseA constructor"，然后调用 BaseB 的构造函数，输出 "BaseB constructor"，最后初始化 Derived 的成员变量 m_e。
在 Derived 构造函数执行完成后，调用 obj 的 show() 函数，输出 m_a、m_b、m_c、m_d 和 m_e 的值。
main 函数执行完成后，销毁了 obj 对象，调用了 Derived 的析构函数，输出 "Derived destructor"；接着调用 BaseB 的析构函数，输出 "BaseB destructor"；最后调用 BaseA 的析构函数，输出 "BaseA destructor"。
BaseA constructor
BaseB constructor
Derived constructor
1,2,3,4,5
Derived destructor
BaseB destructor
BaseA destructor
我觉得没什么好分析的，无非就是构造函数的调用顺序，简单来说一句话，构造从基类开始，析构从派生类开始
不知道你这个问题是否已经解决, 如果还没有解决的话: