左叶4错在哪里1351

#include 

int main()

{int n;

while(scanf("%d",&n)!=EOF)

{ int a[10][10];

  int i,j,s=0;

   for(i=0;ifor(j=0;i"%d",&a[i][j]);}

   for(i=0;is=s+a[i][0];

   int f=0,t=0;

   for(i=0;ifor(j=0;jt=t+a[i][j];

     if(t==s)

     f=1;

     else

     f=0;

     break;}

     t=0;

    for(i=0;ifor(j=0;jt=t+a[j][i];

     if(t==s)

    f=1;

    else

     f=0;break;}

    t=0;

      for(i=0;it=t+a[i][i];

      if(t==s)

      f=1;

      else 

      f=0;

     t=0;

     for(i=0,j=n-1;i=0;i++,j--)

     t=t+a[i][j];

      if(t==s)

      f=1;

      else

      f=0;

      if(f==1)

      printf("YES\n");

      if(f==0)

      printf("NO\n");

}

return 0;

} 

#include <stdio.h>
#include <string.h>
#include <string.h>
int main(void)
{
    int a[10][10];
    int n;
    int i, j, iPrv, iCur, iFlag;
    iPrv = 0;
    iCur = 0;
    iFlag = 0;
    scanf("%d",&n);
    for (i = 0; i < n;i++)            
    {
        for (j = 0; j < n;j++)            
        {
            scanf("%d",&a[i][j]);
        }
    }
    for (i = 0; i < n;i++)              //对角线之和
    {
        iPrv += a[i][i];
        iCur += a[i][n-1 - i];
    }
    if(iCur != iPrv)
    {
        iFlag = 1;
    }
    for (i = 0; i < n;i++)               //行之和 
    {
        if(iFlag == 1)
        {
            break;
        }
        iCur = 0;
        for (j = 0; j < n;j++)
        {
            iCur += a[i][j];
        }
        if(iCur != iPrv)
        {
            iFlag = 1;
        }
    }
    for (j = 0; j < n;j++)               //列之和
    {
        if(iFlag == 1)
        {
            break;
        }
        iCur = 0;
        for (i = 0; i < n;i++)
        {
            iCur += a[i][j];
        }
        if(iCur != iPrv)
        {
            iFlag = 1;
        }
    }
    if(iFlag == 0)
    {
        printf("YES");
    }
    else
    {
        printf("NO");
    }
    return 0;
}

• 这个问题的回答你可以参考下: https://ask.csdn.net/questions/7537375