PHP:如何显示对象的属性?

I have an object $rows

If I use echo $rows the content is displayed in my html page, however I would like to select only some parts of the content but I cannot see inside the variable how it is structured... thanks

Have you looked at var_dump and friends? var_dump() works purely through side effects, so it's great as a debug aid but useless if you want to do something else with the info it spits out. That's when you reach for var_export() and maybe print_r().

A similar question here on SO shows additional ways to inspect your object - get_object_vars() for the object's state, for instance.

Try

print_r($rows);

to see the structure, then use

$rows['property_name'];

to access single properties

Use var_dump/print_r or the XDebug extension to inspect your vars/objects.