请问这个报错怎么解决?

在运行代码的过程中遇到报错 TypeError: forward() takes 2 positional arguments but 3 were given

我的代码:


```python
    def _call_impl(self, *input, **kwargs):
        # Do not call functions when jit is used
        full_backward_hooks, non_full_backward_hooks = [], []
        if len(self._backward_hooks) > 0 or len(_global_backward_hooks) > 0:
            full_backward_hooks, non_full_backward_hooks = self._get_backward_hooks()

        for hook in itertools.chain(
                _global_forward_pre_hooks.values(),
                self._forward_pre_hooks.values()):
            result = hook(self, input)
            if result is not None:
                if not isinstance(result, tuple):
                    result = (result,)
                input = result

        bw_hook = None
        if len(full_backward_hooks) > 0:
            bw_hook = hooks.BackwardHook(self, full_backward_hooks)
            input = bw_hook.setup_input_hook(input)

        if torch._C._get_tracing_state():
            result = self._slow_forward(*input, **kwargs)
        else:
            result =self.forward(*input , **kwargs)      #报错
        for hook in itertools.chain(
                _global_forward_hooks.values(),
                self._forward_hooks.values()):
            hook_result = hook(self, input, result)
            if hook_result is not None:
                result = hook_result

报错信息:
Traceback (most recent call last):
  File "train.py", line 237, in 
    main()
  File "train.py", line 234, in main
    train(args, model, train_loader, test_loader, boardio, textio, checkpoint)
  File "train.py", line 122, in train
    train_loss = train_one_epoch(args, model, train_loader, optimizer)
  File "train.py", line 90, in train_one_epoch
    masked_template, predicted_mask = model(template, source)
  File "module.py", line 889, in _call_impl
    t =self.forward(*input , **kwargs)
TypeError: forward() takes 2 positional arguments but 3 were given

Process finished with exit code 1

该回答引用GPTᴼᴾᴱᴺᴬᴵ
报错提示中显示 forward() 方法只需要 2 个位置参数,但实际传入了 3 个参数。您需要检查传入的参数是否符合 forward() 方法的参数定义。
-
在您的代码中,forward() 方法的定义是没有问题的,问题可能出在调用该方法时传入的参数。可以检查传入的 input 参数是否包含了多余的参数,或者检查您调用 model() 方法时传入的参数是否正确。建议您逐步调试代码,逐步检查参数,以定位问题。