现在查出来的数据为null,该怎么把查出来的数据变为”0“(语言-java)

现在查出来的数据为null,该怎么把查出来的数据变为”0“

img

SELECT
    b.* 
FROM
    (
    SELECT
        a.* 
    FROM
        (
        SELECT DISTINCT
            ( SELECT ISNULL( COUNT ( * ), 0 ) FROM XC_Job ) AS TypeCount,
            ( SELECT ISNULL( COUNT ( * ), 0 ) FROM XC_Job WHERE type = 1 ) AS OneCount,
            ( SELECT ISNULL( COUNT ( * ), 0 ) FROM XC_Job WHERE type = 2 ) AS TwoCount,
            ( SELECT ORG_CODE FROM T_SYS_USERINFO WHERE user_code = XC_Job.userid ) AS jobusername 
        FROM
            XC_Job 
        ) a 
    ) b 
WHERE
    1 = 1 
    AND jobusername = 'yjjhcom_zhglb'

'

你可以使用 SQL 的 IFNULL 函数将 NULL 值替换为 0。

以下是你的查询的修改示例:

SELECT
    b.* 
FROM
    (
    SELECT
        a.* 
    FROM
        (
        SELECT DISTINCT
            IFNULL((SELECT COUNT(*) FROM XC_Job), 0) AS TypeCount,
            IFNULL((SELECT COUNT(*) FROM XC_Job WHERE type = 1), 0) AS OneCount,
            IFNULL((SELECT COUNT(*) FROM XC_Job WHERE type = 2), 0) AS TwoCount,
            (SELECT ORG_CODE FROM T_SYS_USERINFO WHERE user_code = XC_Job.userid) AS jobusername 
        FROM
            XC_Job 
        ) a 
    ) b 
WHERE
    1 = 1 
    AND jobusername = 'yjjhcom_zhglb'

使用 IFNULL 函数,如果子查询返回的值为 NULL,则将其替换为 0。

以下答案引用自GPT-3大模型,请合理使用:

'

将上述SQL语句中每组ISNULL函数改为如下代码:
// 将查询结果为null的值替换为0
SELECT 
    b.* 
FROM 
    (
        SELECT 
            a.* 
        FROM 
            (
                SELECT 
                    DISTINCT(
                        COALESCE(
                            (SELECT 
                                COUNT(*)
                            FROM XC_Job), 0)
                        ) AS TypeCount,
                    COALESCE(
                        (SELECT COUNT(*) FROM XC_Job WHERE type=1), 0
                        ) AS OneCount,
                    COALESCE(
                        (SELECT COUNT(*) FROM XC_Job WHERE type = 2 ), 0
                        ) AS TwoCount,
                    (SELECT ORG_CODE FROM T_SYS_USERINFO WHERE user_code=XC_Job.userid) AS jobusername
                FROM XC_Job
            ) a 
    ) b 
WHERE 1=1 AND jobusername='yjjhcom_zhglb'

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