快速排序的算法题
#include
#include
void quicksort(int letf, int right,int* a);
int n;
int main(void)
{
int i, j;
scanf("%d", &n);
int* a = (int*)malloc(sizeof(int) * n);
for (i = 1; i <= n; i++)
scanf("%d", &a[i]);
quicksort(1, n,a);
for (i = 1; i <= n; i++)
printf("%d ", a[i]);
return 0;
}
void quicksort(int left, int right,int* a)
{
int i, j, t, temp;
if (left > right)
return;
temp = a[left];
i = left;
j = right;
while (i != j)
{
while (a[j] >= temp && i < j)
j--;
while (a[i] <= temp && i < j)
i++;
if (i < j)
{
t = a[i];
a[i] = a[j];
a[j] = t;
}
}
a[left] = a[i];
a[i] = temp;
quicksort(left, i - 1,a);
quicksort(i + 1, right,a);
return;
}
结果显示时间超出,不太明白,有什么好的改法吗?
#include <stdio.h>
#include <malloc.h>
void quicksort(int letf, int right,int* a);
int main(void)
{
int i, n = 10;
scanf("%d", &n);
int a[n];
for (i = 0; i < n; i++)
scanf("%d", &a[i]);
quicksort(0, n-1, a);
for (i = 0; i < n; i++)
printf("%d ", a[i]);
return 0;
}
void quicksort(int left, int right,int* a)
{
int i, j, t, temp;
if (left > right)
return;
temp = a[left];
i = left;
j = right;
while (i < j)
{
while (a[j] >= temp && i < j)
j--; // 从右向左找第一个小于temp的数
if (i < j) {
a[i++] = a[j]; // 将小于temp的值放在左边
}
while (a[i] <= temp && i < j)
i++; // 从左向右找第一个大于temp的数
if (i < j) {
a[j--] = a[i]; // 将大于temp的值放在右边
}
}
a[i] = temp;
quicksort(left, i - 1,a);
quicksort(i + 1, right,a);
return;
}