使用python爬取时候访问异常，验证无法通过？

使用python爬取数据时候访问异常，验证无法通过？

运行截图如下

代码如下

from bs4 import BeautifulSoup
import re
import requests

new_url= 'https://baike.baidu.com/item/Python'
headers = {
        "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/104.0.0.0 Safari/537.36"
    }
response = requests.get(new_url, headers=headers).content.decode()
soup = BeautifulSoup(response, 'html.parser')

print(soup)

```

import urllib.request
import urllib.parse

url = 'https://baike.baidu.com/item/' + urllib.parse.quote('python')
headers = {
    'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/67.0.3396.99 Safari/537.36'
}
req = urllib.request.Request(url=url, headers=headers, method='GET')
response = urllib.request.urlopen(req)
text = response.read().decode('utf-8')
print(text)

• 这个问题的回答你可以参考下: https://ask.csdn.net/questions/7631858
• 同时，你还可以查看手册：python-具体异常 中的内容

 
from bs4 import BeautifulSoup
import re
import requests
 
new_url= 'https://baike.baidu.com/item/Python'
headers = {
        "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/104.0.0.0 Safari/537.36"
    }
response = requests.get(new_url, headers=headers)
soup = BeautifulSoup(response, 'html.parser') // 这里是使用bs4解析对象，你还没开始解析呢，输出有啥用
 
print(response .text)  // 这里是打印源代码