json decode删除新行

Find my Json code.

$result  =  { 
        "text_1": 
            [
                { 
                    "text": "Name 
KarSho", 
                    "left": 0, 
                    "right": 0
                }
            ]
    }

I want "text" from this Json in PHP. I used following script,

$json = json_decode($result,true);
if($json && isset($json['text_1']))
{
    $textblock =$json['text_1'][0];
    echo $textblock['text'];
}

It's giving,

Name KarSho

But I want,

Name KarSho

What to do?

Well, to your surpeize, it will give you, Name KarSho as output, But when you render that in HTML (In any Browser), You will not see a new line, because more than one spaces and new lines are ignored by browsers, if you go to view source of the browser, you will see a new line there,

If you want your HTML to show the new line, use

echo nl2br($textblock['text']);

So that your new lines will be converted to <br> tag, and you will see that in your HTML output.

Edit:

If you want to see also in output (as is), You just want

echo json_encode($textblock['text']);

and to remove the quotes,

echo trim(json_encode($textblock['text']), '"');

<?php  
header('Content-Type: text/plain'); 
$result  = '{"text_1": [{"text": "Name 
KarSho", "left": 0,"right": 0}]}';
$json = json_decode($result,true);
if($json && isset($json['text_1']))
{
    $textblock =$json['text_1'][0];
    echo $textblock['text'];
}

    ?>

use header function to disply next line

OP doesn't want a new line, he wants to print also.

You can escape , for example:

$name = "John 
 Will";

echo str_replace("
", "\
", $name);

will output:

John 
 Will