[Error] no match for 'operator%' (operand types are 'std::bitset<15ull>' and 'int')怎么解决？

问题遇到的现象和发生背景

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遇到的现象和发生背景，请写出第一个错误信息

[Error] no match for 'operator%' (operand types are 'std::bitset<15ull>' and 'int')

用代码块功能插入代码，请勿粘贴截图。 不用代码块回答率下降 50%
#include
#include
using namespace std;
int main(){
  //data:
    int Chinese_and_English=0;
    int Enter = 1;
    int one=0;
  //---------------------------------
    printf("Please enter a numbers(0 = Chinese,Greater than 1 = English):");    
    scanf("%d\n",&Chinese_and_English);
    if(Chinese_and_English==1){
        do{
            if(Enter>32678||Enter<0){
                printf("Input error!Please re-enter.\n");
            }
            printf("Please enter a range of numbers (A number from 0 to 32768 and to the power of 2):");
            scanf("%d\n",&Enter);
        }
        while(0==(Enter==1||Enter==2||Enter==4||Enter==8||Enter==16||Enter==32||Enter==64||Enter==128||Enter==256||Enter==512||Enter==1024||Enter==2048||Enter==4096||Enter==8192||Enter==16384||Enter==32678));
        bool The_number_on_the_ith_digit_is_1[Enter*15];
        int number[Enter]={};
        int j;
        for(j=0;j<=15;j++){
            for(int i=0;i1+j*Enter)*(j+1)]=int(((((((((((((((bitset<15>(i+1)%10)%10)%10)%10)%10)%10)%10)%10)%10)%10)%10)%10)%10)%10)%10);
            } 
        }
        for(int n=0;nint Sequence_of_numbers[one*15];
        int m=1;
        for(int c=0;c<15*one;c++){
            Sequence_of_numbers[c]=The_number_on_the_ith_digit_is_1[m*0+c]*1+The_number_on_the_ith_digit_is_1[m*1+c]*2+The_number_on_the_ith_digit_is_1[m*2+c]*4+The_number_on_the_ith_digit_is_1[m*3+c]*8+The_number_on_the_ith_digit_is_1[m*4+c]*16+The_number_on_the_ith_digit_is_1[m*5+c]*32+The_number_on_the_ith_digit_is_1[m*6+c]*64+The_number_on_the_ith_digit_is_1[m*7+c]*128+The_number_on_the_ith_digit_is_1[m*8+c]*256+The_number_on_the_ith_digit_is_1[m*9+c]*512+The_number_on_the_ith_digit_is_1[m*10+c]*1024+The_number_on_the_ith_digit_is_1[m*11+c]*2048+The_number_on_the_ith_digit_is_1[m*12+c]*4096+The_number_on_the_ith_digit_is_1[m*13+c]*8192+The_number_on_the_ith_digit_is_1[m*14+c]*16384+The_number_on_the_ith_digit_is_1[m*15+c]*32678;
        }
        printf("Is there any number you want in the numbers below?\n");
        for(int a=0;aprintf("%d ",Sequence_of_numbers[a]);
        }
    }
    else{
        
    }
    return 0;
}

###### 运行结果及详细报错内容
没有

我的解答思路和尝试过的方法，不写自己思路的，回答率下降-60%

在网上冲浪了好久很久很久以前

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bitset<15>是要干什么
删掉