Possible Duplicate:
Print newline in PHP in single quotes
Difference between single quote and double quote string in php
$unit1 = 'paragrahp1';
$unit2 = 'paragrahp2';
echo '<p>' . $unit1 . '</p>
';
echo '<p>' . $unit2 . '</p>';
This is displaying (on view source):
<p>paragraph1</p>
<p>paragraph2</p>
but isnt what I’m expecting, not printing the new line, what can be?
PHP only interprets escaped characters (with the exception of the escaped backslash \\ and the escaped single quote \') when in double quotes (")
This works (results in a newline):
"
"
This does not result in a newline:
'
'
Escape sequences (and variables too) work inside double quoted and heredoc strings. So change your code to:
echo '<p>' . $unit1 . "</p>
";
PS: One clarification, single quotes strings do accept two escape sequences:
\' when you want to use single quote inside single quoted strings\\ when you want to use backslash literally must be in double quotes!
echo "hello
world";
Output
hello
world
A nice way around this is to use PHP as a more of a templating language
<p>
Hello <span><?php echo $world ?></span>
</p>
Output
<p>
Hello <span>Planet Earth</span>
</p>
Notice, all newlines are kept in tact!
must be in double quotes!
echo '<p>' . $unit1 . "</p>
";
Better use PHP_EOL ("End Of Line") instead. It's cross-platform.
E.g.:
$unit1 = 'paragrahp1';
$unit2 = 'paragrahp2';
echo '<p>' . $unit1 . '</p>' . PHP_EOL;
echo '<p>' . $unit2 . '</p>';
$unit1 = "paragrahp1";
$unit2 = "paragrahp2";
echo '<p>'.$unit1.'</p>';
echo '<p>'.$unit2.'</p>';
Use Tag <p> always when starting with a new line so you don't need to use /n type syntax.