#include <stdio.h>
int main()
{
int x;
int result = 0;
printf("请输入一个整数:");
scanf("%d",&x);
while(x != 0)
{
result = result*10 + x%10;
x = x/10;
}
printf("%d",result);
printf("\n"); //换行
return 0;
}
试试这个
参考如下:
#include<stdio.h>
#include <string.h>
char * op(char c[]);
int main()
{
char x[20];
gets(x);
printf("%s", op(x));
}
char * op(char c[])
{
int length, i = 0;
length = strlen(c);
char t[length], *p;
while(length >= 0)
{
t[i++] = c[length - 1];
length--;
}
p = t;
return p;
}
如有帮助,欢迎点赞+采纳哈!
帮你写了个中英文通用的程序,供参考,谢谢!
#include <stdio.h>
#include <wchar.h>
#include <locale.h>
wchar_t *revers(wchar_t *p)
{
setlocale(LC_ALL, "zh-CN");
size_t n = wcslen(p) - 1;
wchar_t *ptr = &p[n];
static wchar_t str[512], *p0;
p0 = str;
while (ptr >= p)
*p0++ = *ptr--;
*p0 = L'\0';
return str;
}
int main(int argc, char *argv[])
{
wchar_t s[512];
fgetws(s, 512, stdin);
wprintf(L"%ls", revers(s));
return 0;
}