请写出完整的C语言源程序:使用三种while.do·whiile,for)编程实现2+4+6+8+··98+100,并把结果输出.
就是循环嘛,定义一个变量i=0,sum=0然后套路循环,然后循环一次,sum+=i,i+2,循环到I=100,最后把sum输出就可以了
#include<stdio.h>
int main()
{
int n = 2, sum1 = 0, sum2 = 0, sum3 = 0;
while (n <= 100)
{
sum1 += n;
n += 2;
}
n = 2;
do
{
sum2 += n;
n += 2;
}
while (n <= 100);
for (int i = 2; i < 101; i += 2)
{
sum3 += i;
}
printf("sum1=%d\nsum2=%d\nsum3=%d\n", sum1, sum2, sum3);
return 0;
}