说下第4题
可以用循环嵌套的方法解决
外循环处理行数,循环体用if语句判断行数奇偶,再根据行数决定内循环是正向输出还是逆向输出
内循环再控制一下输出个数为5
4
int main()
{
int row = 4, col = 5, i, j, num = 11, t;
for (i = 0; i < row; i++)
{
if (i % 2 == 0)
{
for (j = 0; j < col; j++)
{
printf("%d ", num++);
}
}
else
{
t = num + col - 1;
for (j = col; j > 0; j--)
{
printf("%d ", t--);
num++;
}
}
printf("\n");
}
return 0;
}
9
int main()
{
int days, week, n = 1, tn = 0;
scanf("%d%d", &days, &week);
while (tn < week)
{
printf("%4c",' ');
tn++;
}
while (n <= days)
{
printf("%4d", n++);
tn++;
if (tn % 7 == 0)
printf("\n");
}
return 0;
}