用51单片机完成一个数字输入显示器，通过矩阵键盘完成数值的输入

问题遇到的现象和发生背景

用51单片机完成一个数字输入显示器，通过矩阵键盘完成数值的输入
没反应
如果可以的话帮忙告诉我怎么利用独立按键实现清零，退格

用代码块功能插入代码，请勿粘贴截图

#include <reg51.h>

sbit dula=P2^6;
sbit wela=P2^7;

unsigned char shuzi[] = { 0x3f,0x06,0x5b,0x4f,
0x66,0x6d,0x7d,0x07,
0x7f,0x6f,0x77,0x7c,
0x39,0x5e,0x79,0x71 };

void delay(unsigned int i)
{
unsigned int m,n;
for(m=i;m>0;m--)
for(n=90;n>0;n--);
}//ÑÓʱ
unsigned char code table[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};
//λѡ
unsigned char juzhen()//
{
unsigned char juzhenNum;
P3 = 0x7f;
if (P3^4 == 0) { delay(20); while (P3^4 == 0); delay(20); juzhenNum = 0; }
if (P3^5 == 0) { delay(20); while (P3^5 == 0); delay(20); juzhenNum = 1; }
if (P3^6 == 0) { delay(20); while (P3^6 == 0); delay(20); juzhenNum = 2; }
if (P3^7 == 0) { delay(20); while (P3^7 == 0); delay(20); juzhenNum = 3; }
P3 = 0xbf;
if (P3^4 == 0) { delay(20); while (P3^4 == 0); delay(20); juzhenNum = 4; }
if (P3^5 == 0) { delay(20); while (P3^5 == 0); delay(20); juzhenNum = 5; }
if (P3^6 == 0) { delay(20); while (P3^6 == 0); delay(20); juzhenNum = 6; }
if (P3^7 == 0) { delay(20); while (P3^7 == 0); delay(20); juzhenNum = 7; }
P3 = 0xdf;
if (P3^4 == 0) { delay(20); while (P3^4 == 0); delay(20); juzhenNum = 8; }
if (P1^5 == 0) { delay(20); while (P3^5 == 0); delay(20); juzhenNum = 9; }
if (P1^6 == 0) { delay(20); while (P3^6 == 0); delay(20); juzhenNum = 10; }
if (P1^7 == 0) { delay(20); while (P3^7 == 0); delay(20); juzhenNum = 11; }
P3 = 0xef;
if (P3^4 == 0) { delay(20); while (P3^4 == 0); delay(20); juzhenNum = 12; }
if (P3^5 == 0) { delay(20); while (P3^5 == 0); delay(20); juzhenNum = 13; }
if (P3^6 == 0) { delay(20); while (P3^6 == 0); delay(20); juzhenNum = 14; }
if (P3^7 == 0) { delay(20); while (P3^7 == 0); delay(20); juzhenNum = 15; }
return juzhenNum;
}
void main()
{

unsigned char num;
while(1)
{
    for(num=0;num<8;num++)
    {
        int i;
        i=juzhen();
        P0=table[num];       
        wela=1;
        wela=0;

        P0=shuzi[i];      
        dula=1;
        dula=0;
        delay(1000);
    }
}

}

16个按键0-9外都可以随意定义功能，退格用一个变量暂存按数字键外的按键可实现参与运算和退格即可，看代码使用锁存器573，独立按键不仅仅单独使用，也可以组成16个按键组，如同矩阵一样使用.573锁存器和矩阵可参如下代码，要复制代码到博客找荔枝代码写法是一样的。

https://img-blog.csdnimg.cn/20200603113047176.gif

参考一下

程序实现功能：数码管前两位显示十进制数，00~59，开始为00。按下S1，数值+1，按下S2,数值-1,按下S3，清零，按下S4一次,自动+1,再按一次停止。
下面附上程序：

#include<reg52.h>
#define uchar unsigned char
#define uint unsigned int
 
sbit k1=P3^0;
sbit k2=P3^1;
sbit k3=P3^2;
sbit k4=P3^3;
sbit du=P2^6;
sbit we=P2^7;
uchar counter,num;
uchar code table[]={
0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,
0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71 };
 
uchar code list[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};   //数码管的段选
 
delay_ms(uint ms)
{
    uint i;
    uint j;
    for(i=0;i<ms;i++)
    {
        for(j=0;j<200;j++);
            for(j=0;j<102;j++);
    }
}
 
void display(uchar i)
{
    uchar shi,ge;
    shi = i / 10; //取十位
    ge  = i % 10; //求余，取各位
    
    P0 = 0xff;
    we = 1;
    P0 = list[0]; //点亮第一位数码管
    we = 0;
 
    du = 1;
    P0 = table[shi];
    du = 0;
    delay_ms(1);
 
    P0 = 0xff;
    we = 1;
    P0 = list[1];//点亮第二位数码管
    we = 0;
 
    du = 1;
    P0 = table[ge];
    du = 0;
    delay_ms(1);    
}
void init()
{
    TMOD=0x10; //定时器1,工作模式1,16位模式定时器
    TH1=(65535-45827)/256;
    TL1=(65535-45827)%256;  //定时50ms
    //TR1=1;     //启动定时器
}
 
void key()
{
    if(k1==0)
    {
        delay_ms(10);
        if(k1==0)
        {
            num++;
            if(num==60)
                num=0;
            while(!k1); //等待按键释放
        }
    }
    if(k2==0)
    {
        delay_ms(10);
        if(k2==0)
        {
            if(num==0)
                num=60;
            num--;
            while(!k2); //等待按键释放
        }
    }
    if(k3==0)
    {
        delay_ms(10);
        if(k3==0)
        {
            num=0;
            while(!k3); //等待按键释放
        }
    }
    if(k4==0)
    {
        delay_ms(10);
        if(k4==0)
        {    
            TMOD=0x10;
            TH1=(65535-45827)/256;
            TL1=(65535-45827)%256;
            TR1=1;
            while(1)
            {    if(TF1==1)
                {
    
                    TF1=0;
                    TH1=(65535-45827)/256;
                    TL1=(65535-45827)%256;  //定时50ms
                    counter++;
                }
                if(counter==20)
                 {
                    counter=0;
                    num++;
                }
                if(num==60)
                {
                    num=0;
                }
                display(num);    
            }
            while(!k4);      //等待按键释放
            {
                            TR1=~TR1; 
            }
        }
    }
}
 
void main()
{
    init();
    while(1)
    {    
        key();
        display(num);
    }
}