visual 2019 中运行不了.cu的文件，报错为MSB3721
CUDA运行的时候出现的问题：
命令”"C: Program Files NVIDIA GPU Computing Toolkit\CUDAv11.6bin\nvcc.exe"-
gencode=arch=compute 52,code="sm 52,compute 52"--use-local-env-ccbin "C:\Program Files (x86)\Microsoft Visual Studio\2019\CommunityVC\ToolsMSVC\14.29.30133\bin\HostX86x64"-x cu -I"C:\Program Files NVIDIA GPU ComputingToolkit\CUDA\v11.6\include"-I"C:\Program Files\NVIDIA GPU Computing Toolkit\CUDA\v11.6\include"-G --keep-dirx64\Debug -maxrregcount=0 --machine 64--compile-cudart static -g -D DEBUG -
D CONSOLE -D UNICODE-DUNICODE-Xcompiler"/EHsc/W3/nologo/Od/Fdx64\Debug\vc142.pdb/FS/Zi/RTC1 MDd"-o D:\VS1\Project7\x64\Debug\File.cu.obj"D:\VS1\Project7\File.cu""已退出，返回代码为1。
Hi, 这个问题主要是关于CUDA开发问题。我尝试去查询了MSB372这个错误，它是一个比较general的报错，你可以在VS中，工具-选择-项目和解决方案 > 生成和运行,找到“MSBuild 项目生成输出详细信息”并设置为‘详细’，然后再运行这项目看看有没有更加具体的错误信息。然后我们可以尝试把问题发到这个专门的CUDA帮助论坛： https://forums.developer.nvidia.com/c/accelerated-computing/cuda/cuda-setup-and-installation/8， 我看到有些报错问题都是在这边寻求帮助的。
/*producer-customer.c*/
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <fcntl.h>
#include <pthread.h>
#include <errno.h>
#include <semaphore.h>
#include <sys/ipc.h>
#define MYFIFO "myfifo" /* 缓冲区有名管道的名字 */
#define BUFFER_SIZE 3 /* 缓冲区的单元数 */
#define UNIT_SIZE 5 /* 每个单元的大小 */
#define RUN_TIME 30 /* 运行时间 */
#define DELAY_TIME_LEVELS 5.0 /* 周期的最大值 */
int fd;
time_t end_time;
sem_t mutex, full, avail; /* 3个信号量 */
/*生产者线程*/
void *producer(void *arg)
{
int real_write;
int delay_time = 0;
while(time(NULL) < end_time)
{
delay_time = (int)(rand() * DELAY_TIME_LEVELS/(RAND_MAX) / 2.0) + 1;
sleep(delay_time);
/*P操作信号量avail和mutex*/
sem_wait(&avail);
sem_wait(&mutex);
printf("\nProducer: delay = %d\n", delay_time);
/*生产者写入数据*/
if ((real_write = write(fd, "hello", UNIT_SIZE)) == -1)
{
if(errno == EAGAIN)
{
printf("The FIFO has not been read yet.Please try later\n");
}
}
else
{
printf("Write %d to the FIFO\n", real_write);
}
/*V操作信号量full和mutex*/
sem_post(&full);
sem_post(&mutex);
}
pthread_exit(NULL);
}
/* 消费者线程*/
void *customer(void *arg)
{
unsigned char read_buffer[UNIT_SIZE];
int real_read;
int delay_time;
while(time(NULL) < end_time)
{
delay_time = (int)(rand() * DELAY_TIME_LEVELS/(RAND_MAX)) + 1;
sleep(delay_time);
/*P操作信号量full和mutex*/
sem_wait(&full);
sem_wait(&mutex);
memset(read_buffer, 0, UNIT_SIZE);
printf("\nCustomer: delay = %d\n", delay_time);
if ((real_read = read(fd, read_buffer, UNIT_SIZE)) == -1)
{
if (errno == EAGAIN)
{
printf("No data yet\n");
}
}
printf("Read %s from FIFO\n", read_buffer);
/*V操作信号量avail和mutex*/
sem_post(&avail);
sem_post(&mutex);
}
pthread_exit(NULL);
}
int main()
{
pthread_t thrd_prd_id,thrd_cst_id;
pthread_t mon_th_id;
int ret;
srand(time(NULL));
end_time = time(NULL) + RUN_TIME;
/*创建有名管道*/
if((mkfifo(MYFIFO, O_CREAT|O_EXCL) < 0) && (errno != EEXIST))
{
printf("Cannot create fifo\n");
return errno;
}
/*打开管道*/
fd = open(MYFIFO, O_RDWR);
if (fd == -1)
{
printf("Open fifo error\n");
return fd;
}
/*初始化互斥信号量为1*/
ret = sem_init(&mutex, 0, 1);
/*初始化avail信号量为N*/
ret += sem_init(&avail, 0, BUFFER_SIZE);
/*初始化full信号量为0*/
ret += sem_init(&full, 0, 0);
if (ret != 0)
{
printf("Any semaphore initialization failed\n");
return ret;
}
/*创建两个线程*/
ret = pthread_create(&thrd_prd_id, NULL, producer, NULL);
if (ret != 0)
{
printf("Create producer thread error\n");
return ret;
}
ret = pthread_create(&thrd_cst_id, NULL, customer, NULL);
if(ret != 0)
{
printf("Create customer thread error\n");
return ret;
}
pthread_join(thrd_prd_id, NULL);
pthread_join(thrd_cst_id, NULL);
close(fd);
unlink(MYFIFO);
return 0;
}
4．实验结果
运行该程序，得到如下结果：
$ ./producer_customer
……
Producer: delay = 3
Write 5 to the FIFO
Customer: delay = 3
Read hello from FIFO
Producer: delay = 1
Write 5 to the FIFO
Producer: delay = 2
Write 5 to the FIFO
Customer: delay = 4
Read hello from FIFO
Customer: delay = 1
Read hello from FIFO
Producer: delay = 2
Write 5 to the FIFO