# 设10元最多用ten张,5元最多用five张
ten = 100//10
sum = 0
for i in range(ten + 1):
five = (100 - i * 10)//5
for j in range(five + 1):
k = 100 - i * 10 - 5 * j
print("ten%d five%d one%d" %(i, j, k))
sum += 1
print("总共有%d种方案" %sum)