设走1阶步数为x,2阶步数为y,3阶步数为z。假如共40阶台阶,则x+2y+3z=40程序大概这样,最后N种走法数。for(x=0;x<=40;x++){ for(y=0;y<=20;y++) { for(z=0;z<=14;z++) { if(x+2y+3z==40) N++; } }}